Calculate the weight percent of ascorbic acid in a tablet of Vitamin C using correct significant figures from the following data: A 90 mg sample of a crushed Vitamin C tablet was dissolved in 40 mL of H2SO4 and 20 mL of water. Two grams of KI and 20. mL of 0.0120 M KIO3 solution was added, and the mixture titrated to a starch endpoint. The titration required 12 mL of 0.0530 M thiosulfate solution. Weight = _____ %

Calculate the weight percent of ascorbic acid in a tablet of Vitamin C using correct significant figures from the following data: A 90 mg sample of a crushed Vitamin C tablet was dissolved in 40 mL of H2SO4 and 20 mL of water. Two grams of KI and 20. mL of 0.0120 M KIO3 solution was added, and the mixture titrated to a starch endpoint. The titration required 12 mL of 0.0530 M thiosulfate solution. Weight = _____ %

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter13: The Chemistry Of Solutes And Solutions

Section: Chapter Questions

Problem 57QRT

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A 500.00 mg vitamin C (MW176.12g/mol) tablet was ground, acidified, and dissolved in H2O to make a 250.0 mL solution. A 50.00 mL aliquot containing vitamin C, KI and starch was analyzed and titrated with 12.31 mL of 0.01042 M KIO3. What is the % (w/w) vitamin C in the tablet? KIO3 + 5 KI + 6 H+ = 3 I2 + 6 K+ + 3 H2O C6H8O6 + I2 = C6H6O6 + 2I- + 2H+ A 67.77 % B 33.89 % C 22.59 % D 3.39 %
A 0.200-g fat was reacted with excess ICl. The remaining ICl was reacted with KI to form I2 and the iodine formed was titrated against a 0.100-N Na2 S2O3 and consumed 43.5-mL of the titrant. A blank analysis was performed, and 65.0-mL of the titrant was used. Calculate the iodine number of the fat.
Calculate the final molarity of H2O2H2O2 if 1.3 mL1.3 mL of the 3.0% w/w H2O23.0% w/w H2O2 solution is diluted with 3.7 mL3.7 mL water, then added to 5.0 mL5.0 mL of a starch-iodide solution.
In the preparation of the standard curve for protein analysis, 50 mn BSA (bovine serum albumin) dissolved in H2O to a final volume of 5 mL was used as stock solution. What is the weight of BSA in 0.1 mL of stock solution? In 0.2 mL?
In iodometry, a student forgot to add H2SO4 before the addition of KI. Is there a positive error, negative error, no effect, or error could not be determined In terms of the Amount of S2O32- used to reach starch endpoint
In a solution containing 25ml (NH4)2S2O8 with a total volume = 100 ml =0.1 liters , the solution composition are shown below.Note; the solution require 25ml of 0.2M S2O8^-2.SOLUTION Kl KNO3 EDTA Na2S2O3 STARCH50ml 23ml 1 drop 1 ml 10 dropsExperiment; initial (S2O8-2) =0.05M ; INITIAL (l-)=0.10 Mml of S2O3^-2 added Time in minutes and seconds for color change Cumulative time in seconds Total moles of S2O8^-2 consumed1 1:43 2.0 x 10^-42 1:20 4.0 x 10^-43 1:13 6.0 x 10 ^-44 1.17 8.0 x 10 ^-45 1.24 10 x 10 ^-41a) Find the cumulative time in secondsb) for the runs ,plot mole of S2O8^2- REACTION vs. time in seconds2) Draw a straight line through ( origin ) the points and calculate the slope3) divide the value of the slope by the total volume of ( 0.1 L) to get the rate in units of M/s4) find the rate5 )calculate x and y and k
Cassava tuber has a composition of 5.76% moisture, 6% protein, 0.2% fat and 34.3 total carbohydrates, 1.6% fiber and 0.3% ash. Find the composition on dry basis.
A 0.9134-g of KIO3 is dissolved in 500-mL distilled water. A 50.0-mL aliquot portion was run down into an Erlenmeyer flask and 2-g of KI and 2-mL of 6M HCl were added to it. Directly after, the solution was titrated with a 24.47-mL Na2S2O3 solution to a faint yellow solution. Starch TS was added to the resulting solution and the titration with the Na2S2O3 solution continued wherein an additional 1.33-mL was required to bring the blue color of the solution to disappear completely. MW: KIO3 = 214.0 g/mol ; Na2S2O3 = 158.1 g/mol Compute the M of the Na2S2O3 solution. 0.1047 M None of the choices 0.1107 M 0.09926 M
A 0.9000-g of KIO3 is dissolved in 500-mL distilled water. A 50.0-mL aliquot portion was run down into an Erlenmeyer flask and 2-g of KI and 2-mL of 6M HCl were added to it. Directly after, the solution was titrated with a 24.80-mL Na2S2O3 solution to a faint yellow solution. Starch TS was added to the resulting solution and the titration with the Na2S2O3 solution continued wherein an additional 1.33-mL was required to bring the blue color of the solution to disappear completely. MW: KIO3 = 214.0 g/mol ; Na2S2O3 = 158.1 g/mol Compute the N of the Na2S2O3 solution. None of the choices 0.09657 N 0.1075 N 0.1017 N
One mL of saliva was diluted to 5 mL using distilled water.A 2.00 mL aliquot was obtained and added to 10 mL of 1% starch solution. Form this solution, 0.5 mL was taken and diluted to 5 mL. Calculate the dilution factor.
Aspartic acid is a polyprotic system whose forms can be written as H3A+, H2A, HA-, and A2-. Its Ka values are: Ka1 = 1.02 x 10-2 Ka2 = 1.26 x 10-4 Ka3 = 9.95 x 10-11 How many milliliters of 0.30 M NaOH should be added to 100 mL of a solution containing 8.0 g of the neutral, zwitterionic form of aspartic acid (M.W. = 133.10 g/mol) to bring the pH to 10.3? Find the answer to the nearest mL. The answer is between 300 and 400. Retain 4 d.p. in your calculations and don't round until you calculate the volume of NaOH required at the very end.
A 25 mL liquid bleach sample is diluted with water to 1000 mL in a bubble gel. 25 mL of the diluted sample is transferred to the flask with a pipette, excess KI is added to it, and thus OCl- ion turns into Cl- ion and I2 is formed. The released iodine is titrated with 0.09892 Na2S2O3 using the starch reagent, and 8.96 mL is required for the endpoint. Find the % NaOCl (w/v; w/v) in the bleach sample. (Na=23 g/mol, O= 16 g/mol, Cl = 35.44 g/mol) (Warning: solving the necessary reaction equations by writing is necessary to see the stoichiometric relationship)