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Calculate ΔHf0 of HPO3 given the data below                    P4O10  +  4 HNO3   ---->  4 HPO3   +  2 N2O5    ΔHorxn = -180.6 kJ             ΔHf0  (kJ/mol)     -2984        -174.1                x             -43.1        a) -528.0 kJ/mol          b) -1471 kJ/mol      c) –943.7 kJ/mol      d) 1471 kJ/mol    e) -954.5 kJ/mol

Calculate ΔHf0 of HPO3 given the data below                    P4O10  +  4 HNO3   ---->  4 HPO3   +  2 N2O5    ΔHorxn = -180.6 kJ             ΔHf0  (kJ/mol)     -2984        -174.1                x             -43.1        a) -528.0 kJ/mol          b) -1471 kJ/mol      c) –943.7 kJ/mol      d) 1471 kJ/mol    e) -954.5 kJ/mol

Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter16: Spontaneity Of Reaction
Section: Chapter Questions
Problem 68QAP: Given that H f for HF(aq) is -320.1 kJ/mol and S for HF(aq) is 88.7 J/mol K, find Ka for HF at 25C.
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Calculate ΔHf0 of HPO3 given the data below

                   P4O10  +  4 HNO3   ---->  4 HPO3   +  2 N2O5    ΔHorxn = -180.6 kJ

            ΔHf0  (kJ/mol)     -2984        -174.1                x             -43.1

       a) -528.0 kJ/mol          b) -1471 kJ/mol      c) –943.7 kJ/mol      d) 1471 kJ/mol    e) -954.5 kJ/mol

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