Calculation to Determine HOClag) Concentration:0.01622L NaOH(aq) x 10moi NaOH1.1 mol NoOH0.0100Z HCIImol HCI12 NGOH= 0.001622 HCl(aq)mo!-3= 1.62 x 10 HCl(agmo! Average Volume of NaOH used:16.3mL +16.3ml + 16.1ml + 16.3mL +16.1mLV.average= 16.22mL NaOHag)Uncertainty on average volume:0.05+0.05 +0.05 + 0.05 + 0.05AUerage= 0.05mLFinal answer: 16.22 + 0.05mLMolar Concentration of HClag:Reaction EquationHCl(aq) - NaOH aq) - NaCl aq) – H2O()OH sa = 16. 22ml x -1000ml

Volumetric titration is a technique used in quantitative analysis. It is used to estimate the amount…

Answered: Calculation to Determine HCl(ag)…

Calculation to Determine HCl(ag) Concentration: 0.01622L NaOH(aq) x 1 mol NaOH 0.0100L HCI 0.10mol NaOH Imol HCI 12 NAOH = 0.001622 HCI(aq) %3D mol -3 L = 1.62 x 10 HCl(aq)T mo!

Appl Of Ms Excel In Analytical Chemistry

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Chapter12: Spectrochemical Methods

Section: Chapter Questions

Problem 3P

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Calculation to Determine HOClag) Concentration:
0.01622L NaOH(aq) x 10moi NaOH
1.
1 mol NoOH
0.0100Z HCI
Imol HCI
12 NGOH
= 0.001622 HCl(aq)
mo!
-3
= 1.62 x 10 HCl(ag
mo!

Average Volume of NaOH used:
16.3mL +16.3ml + 16.1ml + 16.3mL +16.1mL
V.
average
= 16.22mL NaOHag)
Uncertainty on average volume:
0.05+0.05 +0.05 + 0.05 + 0.05
AUerage
= 0.05mL
Final answer: 16.22 + 0.05mL
Molar Concentration of HClag:
Reaction Equation
HCl(aq) - NaOH aq) - NaCl aq) – H2O()
OH sa = 16. 22ml x -
1000ml

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