Carbon disulfide and chlorine react according to the following equation: CS2(g) + 3C12(g) =S2C12(g) + CC14(g) In an experiment, 1.00 mol of CS2 and 3.00 mol of Cl2 are placed in a 2.00 L to react. When the system reaches equilibrium, the mixture contains 0.250 mol of CCI4. What is the amount of Cl2 at equilibrium? 0.25 mol 0.75 mol 2.25 mol 0.50 mol 2.75 mol

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