Carbon disulfide and chlorine react according to the following equation: CS2(g) + 3Cl2(g)  ↔  S2Cl2(g) + CCl4(g) When 2.34 mol of CS2 and 3.21 mol of Cl2 are placed in a 3.38-L container and allowed to come to equilibrium, the mixture is found to contain 0.65 mol of CCl4. How many moles of Cl2 are present at equilibrium?

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Chapter14: Chemical Equilibirum
Section: Chapter Questions
Problem 14.13QP: A chemist put 1.18 mol of substance A and 2.85 mol of substance B into a 10.0-L flask, which she...
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Carbon disulfide and chlorine react according to the following equation:

CS2(g) + 3Cl2(g)  ↔  S2Cl2(g) + CCl4(g)

When 2.34 mol of CS2 and 3.21 mol of Cl2 are placed in a 3.38-L container and allowed to come to equilibrium, the mixture is found to contain 0.65 mol of CCl4. How many moles of Cl2 are present at equilibrium?

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