Carbon tetrachloride (CCl) is diffusing through benzene (CgHe), as the drawing illustrates. The concentration of CCl, at the left end of the tube is maintained at 1.65 x 102 kg/m, and the diffusion constant is 19.5 x 1010 m2/s. The CCI, enters the tube at a mass rate of 5.56 x 10°13 kg/s. Using these data and those shown in the drawing, find (a) the mass of CCl, per second that passes point A and (b) the concentration of CCl, at point A. 5.00 x 10m Cross-sectional area 3.00 x 10m?

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Chapter5: Gases
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Chapter 14, Problem 50
Carbon tetrachloride (CCI4) is diffusing through benzene (CgHs), as the drawing illustrates. The concentration of CCI, at the left end of the tube is maintained at 1.65 x 10-2 kg/m3, and the diffusion constant is 19.5 x 10-10 m2/s. The CCI4 enters the tube at a mass rate of 5.56
x 1013 kg/s. Using these data and those shown in the drawing, find (a) the mass of CCI4 per second that passes point A and (b) the concentration of CCl, at point A.
5.00 x 10-3 m
Cross-sectional
area = 3.00 x 10-4 m2
Transcribed Image Text:Chapter 14, Problem 50 Carbon tetrachloride (CCI4) is diffusing through benzene (CgHs), as the drawing illustrates. The concentration of CCI, at the left end of the tube is maintained at 1.65 x 10-2 kg/m3, and the diffusion constant is 19.5 x 10-10 m2/s. The CCI4 enters the tube at a mass rate of 5.56 x 1013 kg/s. Using these data and those shown in the drawing, find (a) the mass of CCI4 per second that passes point A and (b) the concentration of CCl, at point A. 5.00 x 10-3 m Cross-sectional area = 3.00 x 10-4 m2
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