Challenge Problems 119. Three electrochemical cells were connected in series so b. Hydroxide ion interferes with the measurement of F. Therefore, the response of a fluoride electrode is that the same quantity of electrical current passes through all three cells. In the first cell, 1.15 g of chromium metal was deposited from a chromium(III) nitrate solution. In the second cell, 3.15 g of osmium was deposited from a solution made of Os*+ and nitrate ions. What is the name of the salt? In the third cell, the electrical charge passed through a solution containing X2+ ions caused deposi- tion of 2.11 g of metallic X. Identify X. Emeas = Et - 0.05916 log([F-] + k[OH-]) where k = 1.00 x 10' and is called the selectivity factor for the electrode response. Calculate [F-] for the data in part a if the pH is 9.00. What is the per- cent error introduced in the [F-] if the hydroxide interference is ignored? c. For the [F-] in part b, what is the maximum pH such that [F-/k[OH-] = 50.? d. At low pH, F- is mostly converted to HF. The fluo- ride electrode does not respond to HF. What is the minimum pH at which 99% of the fluoride is pres- ent as F- and only 1% is present as HF? e. Buffering agents are added to solutions containing fluoride before making measurements with a fluoride-selective electrode. Why? 120. An electrochemical cell is set up using the following unbalanced reaction: N2+(aq) + M(s) M**(aq) + N(s) The standard reduction potentials are Ma+ + ae – g° = +0.400 V N2+ + 2e- g° = +0.240 V The cell contains 0.10 M N2+ and produces a voltage of 0.180 V. If the concentration of M-+ is such that the value of the reaction quotient Q is 9.32 × 10-3, calcu- late [M*+]. Calculate wmax for this electrochemical cell. 123. When copper reacts with nitric acid, a mixture of NO(g) and NO2(g) is evolved. The volume ratio of the two product gases depends on the concentration of the nitric acid according to the equilibrium 121. A zinc-copper battery is constructed as follows: 2H*(aq) + 2NO;-(aq) + NO(g) = 3NO2(g) + H2O(1) Zn|Zn²*(0.10 M)||Cu²*(2.50 M)|Cu Consider the following standard reduction potentials at The mass of each electrode is 200. g. a. Calculate the cell potential when this battery is first 25°C: NO(g) + 2H2O(1) 3e- + 4H*(aq) + NO3-(aq) connected. b. Calculate the cell potential after 10.0 A of current has flowed for 10.0 h. (Assume each half-cell con- tains 1.00 L of solution.) c. Calculate the mass of each electrode after 10.0 h. d. How long can this battery deliver a current of 10.0 A before it goes dead? E° = 0.957 V e- + 2H*(aq) + NO; (aq) → NO2(g) + H,O(1) E° = 0.775 V a. Calculate the equilibrium constant for this reaction. b. What concentration of nitric acid will produce an NO and NO, mixture with only 0.20% NO, (by moles) at 25°C and 1.00 atm? Assume that no other gases are present and that the change in acid con- centration can be neglected. 122. The measurement of F ion concentration by ion- selective electrodes at 25.00°C obeys the equation Emcas = Eret – 0.05916 log[F¯] a. For a given solution, Emcas is 0.4462 V. If E,f is 0.2420 V, what is the concentration of F- in the solution?

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ISBN:9781133611097
Author:Steven S. Zumdahl
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Chapter18: Electrochemistry
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Problem 115AE: The saturated calomel electrode. abbreviated SCE. is often used as a reference electrode in making...
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The Image below is from Chemical principles 10th, Zumdahl. I want to know, in problem 122.b, why it questions "the maximum pH". Isn't the only solution "pH = 7.70"?

Please forgive my poor English. I am a student from Taiwan.

Challenge Problems
119. Three electrochemical cells were connected in series so
b. Hydroxide ion interferes with the measurement of
F. Therefore, the response of a fluoride electrode is
that the same quantity of electrical current passes through
all three cells. In the first cell, 1.15 g of chromium metal
was deposited from a chromium(III) nitrate solution. In
the second cell, 3.15 g of osmium was deposited from a
solution made of Os*+ and nitrate ions. What is the name
of the salt? In the third cell, the electrical charge passed
through a solution containing X2+ ions caused deposi-
tion of 2.11 g of metallic X. Identify X.
Emeas = Et - 0.05916 log([F-] + k[OH-])
where k = 1.00 x 10' and is called the selectivity
factor for the electrode response. Calculate [F-] for
the data in part a if the pH is 9.00. What is the per-
cent error introduced in the [F-] if the hydroxide
interference is ignored?
c. For the [F-] in part b, what is the maximum pH
such that [F-/k[OH-] = 50.?
d. At low pH, F- is mostly converted to HF. The fluo-
ride electrode does not respond to HF. What is the
minimum pH at which 99% of the fluoride is pres-
ent as F- and only 1% is present as HF?
e. Buffering agents are added to solutions containing
fluoride before making measurements with a
fluoride-selective electrode. Why?
120. An electrochemical cell is set up using the following
unbalanced reaction:
N2+(aq) + M(s)
M**(aq) + N(s)
The standard reduction potentials are
Ma+ + ae –
g° = +0.400 V
N2+ + 2e-
g° = +0.240 V
The cell contains 0.10 M N2+ and produces a voltage of
0.180 V. If the concentration of M-+ is such that the
value of the reaction quotient Q is 9.32 × 10-3, calcu-
late [M*+]. Calculate wmax for this electrochemical cell.
123. When copper reacts with nitric acid, a mixture of NO(g)
and NO2(g) is evolved. The volume ratio of the two
product gases depends on the concentration of the nitric
acid according to the equilibrium
121. A zinc-copper battery is constructed as follows:
2H*(aq) + 2NO;-(aq) + NO(g) = 3NO2(g) + H2O(1)
Zn|Zn²*(0.10 M)||Cu²*(2.50 M)|Cu
Consider the following standard reduction potentials at
The mass of each electrode is 200. g.
a. Calculate the cell potential when this battery is first
25°C:
NO(g) + 2H2O(1)
3e- + 4H*(aq) + NO3-(aq)
connected.
b. Calculate the cell potential after 10.0 A of current
has flowed for 10.0 h. (Assume each half-cell con-
tains 1.00 L of solution.)
c. Calculate the mass of each electrode after 10.0 h.
d. How long can this battery deliver a current of
10.0 A before it goes dead?
E° = 0.957 V
e- + 2H*(aq) + NO; (aq) → NO2(g) + H,O(1)
E° = 0.775 V
a. Calculate the equilibrium constant for this reaction.
b. What concentration of nitric acid will produce an
NO and NO, mixture with only 0.20% NO, (by
moles) at 25°C and 1.00 atm? Assume that no other
gases are present and that the change in acid con-
centration can be neglected.
122. The measurement of F ion concentration by ion-
selective electrodes at 25.00°C obeys the equation
Emcas = Eret – 0.05916 log[F¯]
a. For a given solution, Emcas is 0.4462 V. If E,f is
0.2420 V, what is the concentration of F- in the
solution?
Transcribed Image Text:Challenge Problems 119. Three electrochemical cells were connected in series so b. Hydroxide ion interferes with the measurement of F. Therefore, the response of a fluoride electrode is that the same quantity of electrical current passes through all three cells. In the first cell, 1.15 g of chromium metal was deposited from a chromium(III) nitrate solution. In the second cell, 3.15 g of osmium was deposited from a solution made of Os*+ and nitrate ions. What is the name of the salt? In the third cell, the electrical charge passed through a solution containing X2+ ions caused deposi- tion of 2.11 g of metallic X. Identify X. Emeas = Et - 0.05916 log([F-] + k[OH-]) where k = 1.00 x 10' and is called the selectivity factor for the electrode response. Calculate [F-] for the data in part a if the pH is 9.00. What is the per- cent error introduced in the [F-] if the hydroxide interference is ignored? c. For the [F-] in part b, what is the maximum pH such that [F-/k[OH-] = 50.? d. At low pH, F- is mostly converted to HF. The fluo- ride electrode does not respond to HF. What is the minimum pH at which 99% of the fluoride is pres- ent as F- and only 1% is present as HF? e. Buffering agents are added to solutions containing fluoride before making measurements with a fluoride-selective electrode. Why? 120. An electrochemical cell is set up using the following unbalanced reaction: N2+(aq) + M(s) M**(aq) + N(s) The standard reduction potentials are Ma+ + ae – g° = +0.400 V N2+ + 2e- g° = +0.240 V The cell contains 0.10 M N2+ and produces a voltage of 0.180 V. If the concentration of M-+ is such that the value of the reaction quotient Q is 9.32 × 10-3, calcu- late [M*+]. Calculate wmax for this electrochemical cell. 123. When copper reacts with nitric acid, a mixture of NO(g) and NO2(g) is evolved. The volume ratio of the two product gases depends on the concentration of the nitric acid according to the equilibrium 121. A zinc-copper battery is constructed as follows: 2H*(aq) + 2NO;-(aq) + NO(g) = 3NO2(g) + H2O(1) Zn|Zn²*(0.10 M)||Cu²*(2.50 M)|Cu Consider the following standard reduction potentials at The mass of each electrode is 200. g. a. Calculate the cell potential when this battery is first 25°C: NO(g) + 2H2O(1) 3e- + 4H*(aq) + NO3-(aq) connected. b. Calculate the cell potential after 10.0 A of current has flowed for 10.0 h. (Assume each half-cell con- tains 1.00 L of solution.) c. Calculate the mass of each electrode after 10.0 h. d. How long can this battery deliver a current of 10.0 A before it goes dead? E° = 0.957 V e- + 2H*(aq) + NO; (aq) → NO2(g) + H,O(1) E° = 0.775 V a. Calculate the equilibrium constant for this reaction. b. What concentration of nitric acid will produce an NO and NO, mixture with only 0.20% NO, (by moles) at 25°C and 1.00 atm? Assume that no other gases are present and that the change in acid con- centration can be neglected. 122. The measurement of F ion concentration by ion- selective electrodes at 25.00°C obeys the equation Emcas = Eret – 0.05916 log[F¯] a. For a given solution, Emcas is 0.4462 V. If E,f is 0.2420 V, what is the concentration of F- in the solution?
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