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Chemistry 1515R Problem SetConsider the following: HCl + NaOH → NaCl + H2OIf a 20.0 mL sap H was neutralized by 35.2 mL of 0.500 M NaOH:al Calculate the mass of hydrochloric acid present in the acid sample.bl Calculate the molarity of the acid sample.Consider the following:If a 24.0 mL sample of H.SOlo) was neutralized by 20.0 mL of 0.125 M NaOH:al Calculate the mass of sulfuric acid present in the acid sample.52(aq)ESH,so, + 2 NaOH → Na2SO4 + 2 H,O53bl Calculate the molarity of the acid sample.

Question
Chemistry 1515R Problem Set
Consider the following: HCl + NaOH → NaCl + H2O
If a 20.0 mL sap H was neutralized by 35.2 mL of 0.500 M NaOH:
al Calculate the mass of hydrochloric acid present in the acid sample.
bl Calculate the molarity of the acid sample.
Consider the following:
If a 24.0 mL sample of H.SOlo) was neutralized by 20.0 mL of 0.125 M NaOH:
al Calculate the mass of sulfuric acid present in the acid sample.
52
(aq)
ES
H,so, + 2 NaOH → Na2SO4 + 2 H,O
53
bl Calculate the molarity of the acid sample.
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Chemistry 1515R Problem Set Consider the following: HCl + NaOH → NaCl + H2O If a 20.0 mL sap H was neutralized by 35.2 mL of 0.500 M NaOH: al Calculate the mass of hydrochloric acid present in the acid sample. bl Calculate the molarity of the acid sample. Consider the following: If a 24.0 mL sample of H.SOlo) was neutralized by 20.0 mL of 0.125 M NaOH: al Calculate the mass of sulfuric acid present in the acid sample. 52 (aq) ES H,so, + 2 NaOH → Na2SO4 + 2 H,O 53 bl Calculate the molarity of the acid sample.

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Step 1

Question No. 52

The given reaction equation is,

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Step 2

a)

To calculate the mass of Hydrochloric acid present, first find the moles of NaOH.

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Step 3

The given reaction is a neutralization reaction. Therefore, 0.0176 moles of NaOH would neutralize same moles (0.0176 mol...

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