Data of HClTrial 1: volume of HCl =0.82l Volume of NaOH =22.1mlTrial 2: volume of HCl=0.821ml Volume of NaOH = 22.2mlTrial 3: volume of HCl= 0.821ml Volume NaOH = 22.7ml1) calculate the molarity of HCl for each trial and find the average molarity. Procedure:A-Preparation of 100 mL of 0.10M HCIaisiYou need to calculate the volume of concentrated HCI you need to take and dilute it with Water to make100 mL of 0.10 M HCl. (density of concentrated HCl = 1.20 g/ml, mass percent = 37% by mass)B-Preparation of 200 mL of 0.10 M NAOHYou need to calculate the mass of NaOH that you need to weigh and dissolve in 200 mL of water to make200 mL of 0.10 M NaOH.Hint: NaOH pellets should be weighed on a watch glass, mix it well with water. (Caution: NaOH is verycorrosive, do not spill and if you do, wash it off immediately with an excess of water.)C- Standardization of ~0.10M NaOH “Determining the concentration of NaOH"1- Weigh duplicate samples of 0.50-0.60 g of previously dried standard KHP into 125 or 250- ml flasks.Dissolve each sample in ~25.0- ml in distilled water.2 - Add 2-4 drops of phenolphthalein indicator. Titrate it with NaOH until the first appearance of apermanent, pink color.3- If runs do not agree to about two parts per thousand, repeat for the third time and calculate the averageof the two closest results.D- Standardization of HCl "Determining the concentration of HCl"1- Use the NaOH solution that you prepared to determine the concentration of HC.2- Add 2-4 drops of phenolphthalein indicator to a 25.0 mL of the previously prepared HCl and titratewith the NaOH solution until the first appearance of a permanent pink color.3- 3- If runs do not agree to about two parts per thousand, repeat for the third time and calculate theaverage of the two closest results.

Answered: Image /qna-images/answer/5e004e25-2b82-43a3-a246-2e8212076e75.jpg

Data of HCl Trial 1: volume of HCl =0.82l Volume of NaOH =22.1ml Trial 2: volume of HCl=0.821ml Volume of NaOH = 22.2ml Trial 3: volume of HCl= 0.821ml Volume NaOH = 22.7ml 1) calculate the molarity of HCl for each trial and find the average molarity.

Data of HCl Trial 1: volume of HCl =0.82l Volume of NaOH =22.1ml Trial 2: volume of HCl=0.821ml Volume of NaOH = 22.2ml Trial 3: volume of HCl= 0.821ml Volume NaOH = 22.7ml 1) calculate the molarity of HCl for each trial and find the average molarity.

Introduction to General, Organic and Biochemistry

11th Edition

ISBN:9781285869759

Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres

Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres

Chapter6: Solutions And Colloids

Section: Chapter Questions

Problem 6.105P

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