3. What effect will decreasing the pressure of the reaction mixture have on the system? OThe reaction will shift in the direction of products. OThe reaction will shift in the direction of reactants. ONo change will be observed. OThe equilibrium constant will decrease. OThe equilibrium constant will increase. 4. What effect will adding 1 mole of Ar to the reaction mixture (keeping pressure unchanged) have on the system? OThe reaction will shift in the direction of products. OThe reaction will shift in the direction of reactants. ONo change will be observed. OThe equilibrium constant will decrease. OThe equilibrium constant will increase. Consider the following reaction at equilibrium. CO2(g) + 2 H20(1) = CHĄ(g) + 2 O2(g) ΔΗ = +890 kJ 1. What effect will adding H20(I) have on the system? OThe reaction will shift in the direction of products. OThe reaction will shift to the left. ONo change will be observed. OThe equilibrium constant will decrease. OThe equilibrium constant will increase. 2. What effect will decreasing the volume of the container have on the system? OThe reaction will shift in the direction of products. OThe reaction will shift in the direction of reactants. ONo change will be observed. OThe equilibrium constant will decrease. OThe equilibrium constant will increase.

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 61QRT
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3. What effect will decreasing the pressure of the reaction mixture have on the
system?
OThe reaction will shift in the direction of products.
OThe reaction will shift in the direction of reactants.
ONo change will be observed.
OThe equilibrium constant will decrease.
OThe equilibrium constant will increase.
4. What effect will adding 1 mole of Ar to the reaction mixture (keeping pressure
unchanged) have on the system?
OThe reaction will shift in the direction of products.
OThe reaction will shift in the direction of reactants.
ONo change will be observed.
OThe equilibrium constant will decrease.
OThe equilibrium constant will increase.
Transcribed Image Text:3. What effect will decreasing the pressure of the reaction mixture have on the system? OThe reaction will shift in the direction of products. OThe reaction will shift in the direction of reactants. ONo change will be observed. OThe equilibrium constant will decrease. OThe equilibrium constant will increase. 4. What effect will adding 1 mole of Ar to the reaction mixture (keeping pressure unchanged) have on the system? OThe reaction will shift in the direction of products. OThe reaction will shift in the direction of reactants. ONo change will be observed. OThe equilibrium constant will decrease. OThe equilibrium constant will increase.
Consider the following reaction at equilibrium.
CO2(g) + 2 H20(1) = CHĄ(g) + 2 O2(g)
ΔΗ
= +890 kJ
1. What effect will adding H20(I) have on the system?
OThe reaction will shift in the direction of products.
OThe reaction will shift to the left.
ONo change will be observed.
OThe equilibrium constant will decrease.
OThe equilibrium constant will increase.
2. What effect will decreasing the volume of the container have on the system?
OThe reaction will shift in the direction of products.
OThe reaction will shift in the direction of reactants.
ONo change will be observed.
OThe equilibrium constant will decrease.
OThe equilibrium constant will increase.
Transcribed Image Text:Consider the following reaction at equilibrium. CO2(g) + 2 H20(1) = CHĄ(g) + 2 O2(g) ΔΗ = +890 kJ 1. What effect will adding H20(I) have on the system? OThe reaction will shift in the direction of products. OThe reaction will shift to the left. ONo change will be observed. OThe equilibrium constant will decrease. OThe equilibrium constant will increase. 2. What effect will decreasing the volume of the container have on the system? OThe reaction will shift in the direction of products. OThe reaction will shift in the direction of reactants. ONo change will be observed. OThe equilibrium constant will decrease. OThe equilibrium constant will increase.
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