A closed 200mL flask has a pressure of 6atms, a temperature of 51°C and 18.7 particles of gas. If 16.7 particles are added to the flask and the temperature is changed to 40.7°C, what is the new pressure? PV nRT PV n.RT °C+ 273 =K

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A: Given: Pressure of gas = 83.80 KPa. Temperature = 27.64 oC Volume of gas = 1.022 m3

Q: 9. What is the new temperature when 10L at 5 K is compressed to 4.00 L? O 2K 0.5 K 25 K 20 K

A: PV = nRT  At constant pressure and number of moles,  V = K • T  Initial, V1 = K • T1  Final, V2 = K…

Q: Useful conversion factors and equations: P,V1_ P2V2 T2 L· atm mass PV = nRT n = 0.0821 density (d)…

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Q: The temperature of a sample of CH4 gas (76.5 g) in a 50.0L vessel at 1.04atm is ___*C.

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Q: 12. A 60.0 ml cylinder is filled with a mixture of an unknown element M(g) and Cl2(g) to partial…

A: Given, for element M , Volume =60  mLT=30°C=30+273=303KP=3.07 atmtherefore, putting this value in…

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A: From the given data (a) V1= 2.84 L V2= 4.64 L T1=19°C (b) V1= 122 mL T1= 273 K T2= 386 K (c) V1= 39…

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A: Given:: P1=1.65 atm T1=11℃  T2=35℃ P2=?

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Q: If 0.290 mol of an ideal gas has a volume of 1929 and a pressure of 5.50 atmwhat is its temperature…

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Q: What is the pressure (in bar) in a 4.00 L tank with 41.0 grams of oxygen gas at 350.0 K? R = 0.08314…

A: Given data, Volume=4.00LMass of oxygen=41.0gTemperature=350.0KR=0.08314L.bar/mol.K

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Q: Convert the ideal gas constant: R = 1.987 [cal/((gmole)(K))] to [Btu/(lb mol)("degree"R)]

A: Given R = 1.987 [cal/((gmole)(K))]   R = ..?.... [Btu/(lb mol)("degree"R)] =to be determined

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A: As pressure and number of mole remain constant.then according to Charles law              V ∝ T…

Q: 1,000- P 10아 e 10- r e 1아- (atm) 0.1- 0.01- 0.001 40 60 80 100 120 Temperature (C) Suppose a gas is…

A: From graph it is clear that: At 0.01 atm and 100oC the phase is gas. And at 10 atm and 100oC the…

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Q: A gas exerts 59.3 kPa on its container at 25.0 °C. What temperature is needed to increase the…

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