Chlorine gas (Cl2) can be produced from the reaction of potassium permanganate (KMNO4, molar mass= 158.034 g/mol) and hydrochloric acid (HCl) as shown in the following equation:2KMNO4(6) + 16HC((aq) → 8H201) + 2KCI(aq) + 2MnCl2(aq) + 5Cl2(g)If 4.16 g of KMNO4 is reacted with 30.0 mL of 12.01 M HCl at 35 °C and 1.03 atm, how many liters of Cl2 can beproduced?Select one:O a. 1.23 LO b. 1.62 LO c. 1.44 LO d. 1.79 L

We have to calculate the volume of Cl2 Gas produced.

Chlorine gas (Cl,) can be produced from the reaction of potassium permanganate (KMNO4, molar mass = 158.034 g/mol) and hydrochloric acid (HCI) as shown in the following equation: 2KMNO4(6) + 16HCI(aq) → 8H201) + 2KCI(aq) + 2MNC/2(aq) + 5C12(g) If 4.16 g of KMNO4 is reacted with 30.0 mL of 12.01 M HCI at 35 °C and 1.03 atm, how many liters of Cl2 can be produced? Select one: O a. 1.23L O b. 1.62 L 1.44 L O d. 1.79 L

Chlorine gas (Cl,) can be produced from the reaction of potassium permanganate (KMNO4, molar mass = 158.034 g/mol) and hydrochloric acid (HCI) as shown in the following equation: 2KMNO4(6) + 16HCI(aq) → 8H201) + 2KCI(aq) + 2MNC/2(aq) + 5C12(g) If 4.16 g of KMNO4 is reacted with 30.0 mL of 12.01 M HCI at 35 °C and 1.03 atm, how many liters of Cl2 can be produced? Select one: O a. 1.23L O b. 1.62 L 1.44 L O d. 1.79 L

General Chemistry - Standalone book (MindTap Course List)

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ISBN:9781305580343

Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell

Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell

Chapter3: Calculations With Chemical Formulas And Equaitons

Section: Chapter Questions

Problem 3.141QP: A power plant is driven by the combustion of a complex fossil fuel having the formula C11H7S. Assume...

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9781305580343

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