Choose the correct pair of hypotheses for this situation.(A)(B)(C)Ho: p = 0.29 Ho:p = 0.29 Ho:p= 0.29H: p< 0.29 H: p 0.29 H: p> 0.29(F)(E)(D)Ho: p = 0.349 Ho:p = 0.349 Ho:p = 0.349H: p< 0.349 H: p # 0.349 H: p> 0.349(A) (B) (C) (D) (E) (F)Using the normal approximation for the binomial distribution (without the continuity correction), what is the teststatistic for this sample based on the sample proportion?2.554S(Report answer as a decimal accurate to 3 decimal places.)You are now ready to calculate the P-value for this sample.P-value = 0.0107(Report answer as a decimal accurate to 4 decimal placesThis P-value (and test statistic) leads to a decision to.reject the nullaccept the nulfail to raicct the null

Question
Asked Nov 25, 2019
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Choose the correct pair of hypotheses for this situation.
(A)
(B)
(C)
Ho: p = 0.29 Ho:p = 0.29 Ho:p= 0.29
H: p< 0.29 H: p 0.29 H: p> 0.29
(F)
(E)
(D)
Ho: p = 0.349 Ho:p = 0.349 Ho:p = 0.349
H: p< 0.349 H: p # 0.349 H: p> 0.349
(A) (B) (C) (D) (E) (F)
Using the normal approximation for the binomial distribution (without the continuity correction), what is the test
statistic for this sample based on the sample proportion?
2.554
S
(Report answer as a decimal accurate to 3 decimal places.)
You are now ready to calculate the P-value for this sample.
P-value = 0.0107
(Report answer as a decimal accurate to 4 decimal places
This P-value (and test statistic) leads to a decision to.
reject the null
accept the nul
fail to raicct the null
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Choose the correct pair of hypotheses for this situation. (A) (B) (C) Ho: p = 0.29 Ho:p = 0.29 Ho:p= 0.29 H: p< 0.29 H: p 0.29 H: p> 0.29 (F) (E) (D) Ho: p = 0.349 Ho:p = 0.349 Ho:p = 0.349 H: p< 0.349 H: p # 0.349 H: p> 0.349 (A) (B) (C) (D) (E) (F) Using the normal approximation for the binomial distribution (without the continuity correction), what is the test statistic for this sample based on the sample proportion? 2.554 S (Report answer as a decimal accurate to 3 decimal places.) You are now ready to calculate the P-value for this sample. P-value = 0.0107 (Report answer as a decimal accurate to 4 decimal places This P-value (and test statistic) leads to a decision to. reject the null accept the nul fail to raicct the null

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Expert Answer

Step 1

Here, the claim is that the proportion of only children in the special program is significantly different from the proportion for the school district. The alternative hypothesis state no direction. Moreover, there is “≠” symbol in alternative hypothesis. Hence, the test is Two-tailed test.

The hypotheses are given below:

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Null hypothesis: Ho p 0.29 Alternative hypothesis: H p 0.29

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Step 2

Correct Answer: Option (B)

The sample statistic is obtained as follows:

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130 373 0.349

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Step 3

The test statistic is obt...

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Sample statistic Null Parameter SE p-Po Р. 1- Р.) п 0.349-0.29 0.29(1-0.29) 373 =2.511

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