CIF 3(9) AH = ? 2.) CIF9) + F2(g) AH = - 49.4 kJ 20F2(9) Ozlg) + 2F2(9) AH= 205.6 kJ Cl,0(9) + OF219) 2CIF(9) + O219) AH = 266.7 kJ % Cl,0(9) + 3/2 OF2(9) (6), CIF3(9) + O2(g)

Physical Chemistry
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ISBN:9781133958437
Author:Ball, David W. (david Warren), BAER, Tomas
Publisher:Ball, David W. (david Warren), BAER, Tomas
Chapter1: Gases And The Zeroth Law Of Thermodynamics
Section: Chapter Questions
Problem 1.19E: Use the two appropriate values of R to determine a conversion between L. atm and J.
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AH = ?
CIF 3(g)
2.) CIF(9) + F2(g)
AH = - 49.4 kJ
Ozlg) + 2F2(g)
20F2(9)
AH= 205.6 kJ
Cl,O (G) + OF2(g)
+ Ozlg)
2CIF (9) +
+ O2(g)
AH = 266.7 kJ
%3D
½ Cl,0 (G) + 3/2 OF2(9)
CIF319)
Transcribed Image Text:AH = ? CIF 3(g) 2.) CIF(9) + F2(g) AH = - 49.4 kJ Ozlg) + 2F2(g) 20F2(9) AH= 205.6 kJ Cl,O (G) + OF2(g) + Ozlg) 2CIF (9) + + O2(g) AH = 266.7 kJ %3D ½ Cl,0 (G) + 3/2 OF2(9) CIF319)
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