COH H2SO4 (cat) NaOH HO CH3OH B CH3OH 4. H2SO4 (cat) OCH3 H2SO4 (cat) D+E C H20 H20 NaOH G +H H20 OCH3 H2SO4 (cat) HO. Li= H3O* H30* CHO A в он H20 HO
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- Solve this bahin hurry up 2abc Show stepo 10minssend help, I'll give you a rate if you send the correct answer. please don't answer like "7.08x10^23" because it is not accepted sometimes or they need whole number w/o x10^23 something. thanks!You are in lab doing an experiment, so far this is your data: Pb(CH3COO)2 (aq) + H2S (aq) → PbS (s) + CH3COOH (aq) 10g Pb (CH3COO)2 + 3g H2S produce 11.56g of led sulfate + 1.44g S 18g Pb (CH3COO)2 + 1.56g H2S produce 11.56g of led sulfate + 8.00g S Based on this data. What type of reaction is it? How many grams of sulfur do you need to completely react 10.00g of Pb. Balanced equation.
- Please help me solve the following question and make sure its correct 100%, thank you sm1. What is the mEq of silver nitrate? 170 0.0170 0.170 17.0 2. How much (mL) silver nitrate is required for the standardization? 4.995 49.950 49.590 45.990 * MW of silver nitrate = 170 g/mol * Please take note that Im looking for the silver nitrateLet me tell you about their task: The students were provided with 5 drinks (sports/soft drinks) and they were asked to determine the glucose concentration in these drinks in the units of g/100mL. (Why these units? Well, once the students have the concentrations in g/100mL they will be able to compare their values with the nutritional values given on the drink bottles’ labels). The samples of the five drinks were all diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for the students is that the dilution factor will have to be taken into consideration in their calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). The students decided to save time and form five groups where each group was…