CoH12 (1) + 902 (g) 6CO:(g) + 6H;O() For CeH12(0), AH; =- 151.9 kJ/mol. AH; (CO,,g)=-393.5kJ / mol AH; (H,0,1)=-285.8kJ / mol. Molecular oxygen (O2) is a stable allotrope of oxygen. (ii)From the following data, C(graphite) + O2(g) → CO2(9) AHm = -393.5 kJ/mol H2(g) + | 0:(9) → H¿O(1) AH,, = -285.8 kJ/mol 2C;Hs (9) + 70:(9) → 4CO2(g) + 6H;O() AHm =-3119.6 kJ/mol calculate the enthalpy change for the reaction 2C(graphite) + 3H2(9) → C;H«(g) (b) Consider this reaction: 2CH;OH() + 302 → 4H;0() + 2CO2(9) AH = - 1452.8 kJ/mol What is the value of AH if (i) the equation is multiplied throughout by 2, (ii) the direction of the reaction is reversed so that the products become the reactants and vice versa, (ii) water vapor instead of liquid water is formed as the product? Hint: 2H,0(I) –→ 2H,0(g) AH = 88.0kJ / mol

CoH12 (1) + 902 (g) 6CO:(g) + 6H;O() For CeH12(0), AH; =- 151.9 kJ/mol. AH; (CO,,g)=-393.5kJ / mol AH; (H,0,1)=-285.8kJ / mol. Molecular oxygen (O2) is a stable allotrope of oxygen. (ii)From the following data, C(graphite) + O2(g) → CO2(9) AHm = -393.5 kJ/mol H2(g) + | 0:(9) → H¿O(1) AH,, = -285.8 kJ/mol 2C;Hs (9) + 70:(9) → 4CO2(g) + 6H;O() AHm =-3119.6 kJ/mol calculate the enthalpy change for the reaction 2C(graphite) + 3H2(9) → C;H«(g) (b) Consider this reaction: 2CH;OH() + 302 → 4H;0() + 2CO2(9) AH = - 1452.8 kJ/mol What is the value of AH if (i) the equation is multiplied throughout by 2, (ii) the direction of the reaction is reversed so that the products become the reactants and vice versa, (ii) water vapor instead of liquid water is formed as the product? Hint: 2H,0(I) –→ 2H,0(g) AH = 88.0kJ / mol

Chemistry by OpenStax (2015-05-04)

1st Edition

ISBN:9781938168390

Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser

Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser

Chapter5: Thermochemistry

Section: Chapter Questions

Problem 44E: Although the gas used in an oxyacetylene torch (Figure 5.7) is essentially pure acetylene, the heat...

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