Question
Asked Oct 21, 2019

Combining 0.290 mol Fe2O3 with excess carbon produced 13.1 g Fe.

 

Fe2O3+3C⟶2Fe+3CO

 

What is the actual yield of iron in moles?

What is the theoretical yield of iron in moles?

What is the percent yield?

check_circleExpert Solution
Step 1

Given,

The molar mass of Fe is 55.85g/mol

The actual yield of Fe in moles can be calculated as

weight of Fe
Actual yield
Molecular weight of Fe
13.1g
55.85g/mol
Actual yield =
=0.2345mol
Hence, the actual yield is 0.2345mol.
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weight of Fe Actual yield Molecular weight of Fe 13.1g 55.85g/mol Actual yield = =0.2345mol Hence, the actual yield is 0.2345mol.

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Step 2

Theoretical yield of iron in mo...

Given
Fe O, moles 0.290 mole
Theoritical yield of Fe
2x0.290
Theoritical yield of Fe
0.58 mole.
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Given Fe O, moles 0.290 mole Theoritical yield of Fe 2x0.290 Theoritical yield of Fe 0.58 mole.

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