  # Combustion analysis of 1.200 g of an unknown compound containing carbon, hydrogen, and oxygen produced 2.086 g of CO2 and 1.134 g of H2O. What is the empirical formula of the compound?Combustion analysis of 1.200 g of an unknown compound containing carbon, hydrogen, and oxygen produced 2.086 g of CO2 and 1.134 g of H2O. What is the empirical formula of the compound?C2H5OC3H8O2C2H5O2C2H10O3

Question

Combustion analysis of 1.200 g of an unknown compound containing carbon, hydrogen, and oxygen produced 2.086 g of CO2 and 1.134 g of H2O. What is the empirical formula of the compound?
Combustion analysis of 1.200 g of an unknown compound containing carbon, hydrogen, and oxygen produced 2.086 g of CO2 and 1.134 g of H2O. What is the empirical formula of the compound?
C2H5O
C3H8O2
C2H5O2
C2H10O3

check_circleExpert Solution
Step 1

molar mass of CO2 = 44 g/mol

molar mass of carbon = 12 g/mol

1 CO2 has 1 C in it

molar mass of H2O = 18 g/mol

molar mass of H = 1 g/mol

1 H2O has 2 H in it

Step 1: mass of carbon in compound = (2.086 g CO2/44 g/mol) x (12 g/mol) = 0.57 g

Step 2: mass of Hydrogen in the compound = (2) x (1.134 g/18 g/mol) x (1 g/mol) = 0.126 g

Step 3: mass of oxygen in the compound = 1.200 g - (0.57 g + 0.126 g) = 0.5 g

Step 4: conv...

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