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Complete the table. Calculate the cell potential when 20.0 mL of 0.05 M Fe²* was titrated with 0.05 M Ce* in a matrix of 1 M HC104. Answers should be in 3 decimal points. Write the values only, no need for units. The reaction is given as Fe2* +Ce** =Ce3+ +Fe3+ Standard Potentials are Fe3+ +e- →FE2* Eo =+0.767 V and Ce4* +e- →Ce3+ Eo =+1.70 v Vt Ecell, V 10mL 15mL 20mL

Complete the table. Calculate the cell potential when 20.0 mL of 0.05 M Fe²* was titrated with 0.05 M Ce* in a matrix of 1 M HC104. Answers should be in 3 decimal points. Write the values only, no need for units. The reaction is given as Fe2* +Ce** =Ce3+ +Fe3+ Standard Potentials are Fe3+ +e- →FE2* Eo =+0.767 V and Ce4* +e- →Ce3+ Eo =+1.70 v Vt Ecell, V 10mL 15mL 20mL

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter17: Electrochemistry And Its Applications
Section: Chapter Questions
Problem 50QRT
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Complete the table. Calculate the cell potential when 20.0 mL of 0.05 M Fe2* was titrated with 0.05 M Ce4+ in a matrix of 1 M HC104. Answers should be in 3 decimal points. Write the values only, no need for units. The reaction is given as Fe2* +Ce4+ =Ce3+ +Fe3+ Standard Potentials are Fe3+ +e-→F22* Eo =+0.767 V and Ce4+ +e- →Ce3+ Eo =+1.70 v Vt Ecell, V 10mL 15mL 20mL 25mL 30mL
Transcribed Image Text:Complete the table. Calculate the cell potential when 20.0 mL of 0.05 M Fe2* was titrated with 0.05 M Ce4+ in a matrix of 1 M HC104. Answers should be in 3 decimal points. Write the values only, no need for units. The reaction is given as Fe2* +Ce4+ =Ce3+ +Fe3+ Standard Potentials are Fe3+ +e-→F22* Eo =+0.767 V and Ce4+ +e- →Ce3+ Eo =+1.70 v Vt Ecell, V 10mL 15mL 20mL 25mL 30mL
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