Composition Practice ☆回凸 Format Tools Add-ons Help Last edit was 10 days ago Normal text Arial 11 BIUA 主 2 |I Percent Composition Practice Directions: Find the percent composition of each element in the follow 1) (NH,),SO, 2) NaBr 3) CO2 4) Cu(OH)2 5) M9CO; 6) Fe,(PO4), 7) Be,N, 8) MnN 9) Mga(PO.)2 10) AIC, 11) Li,P 12) Al,(SO,)3

Composition Practice ☆回凸 Format Tools Add-ons Help Last edit was 10 days ago Normal text Arial 11 BIUA 主 2 |I Percent Composition Practice Directions: Find the percent composition of each element in the follow 1) (NH,),SO, 2) NaBr 3) CO2 4) Cu(OH)2 5) M9CO; 6) Fe,(PO4), 7) Be,N, 8) MnN 9) Mga(PO.)2 10) AIC, 11) Li,P 12) Al,(SO,)3

Chemistry: Principles and Reactions

8th Edition

ISBN:9781305079373

Author:William L. Masterton, Cecile N. Hurley

Publisher:William L. Masterton, Cecile N. Hurley

Chapter3: Mass Relations In Chemistry; Stoichiometry

Section: Chapter Questions

Problem 89QAP: By x-ray diffraction it is possible to determine the geometric pattern in which atoms are arranged...

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Use the periodic table shown in Fig. 4.9 to determine the atomic mass (per mole) or molar mass of each of the substances in column 1, and find that mass in column 2. l> Column 1 Column 2 (1) molybdenum (a) 33.99 g (2) lanthanum (b) 79.9 g (3) carbon tetrabromide (c) 95.94 g (4) mercury(II)oxide (d) l25.4g (5) titanium(iV) oxide (e) 138.9 g (6) manganese(ll) chloride (f) 143.1 g (7) phosphine, (g) 156.7 g (8) tin(II) fluoride (h) 216.6 g (9) lead(II) sulfide (i) 239.3 g (10) copper(I)oxide (j) 3316g
By x-ray diffraction it is possible to determine the geometric pattern in which atoms are arranged in a crystal and the distances between atoms. In a crystal of silver, four atoms effectively occupy the volume of a cube 0.409 nm on an edge. Taking the density of silver to be 10.5 g/cm3, calculate the number of atoms in one mole of silver.
Suppose Avogadro’s number was 1000 instead of 6.0221023 . How, if at all, would this affect the relative masses on the periodic table? How, if at all, would this affect the absolute masses of the elements?
With the advent of techniques such as scanning tunneling microscopy, it is now possible to write with individual atoms by manipulating and arranging atoms on an atomic surface. a. If an image is prepared by manipulating iron atoms and their total mass is 1.05 1020 g, what number of iron atoms were used? b. If the image is prepared on a platinum surface that is exactly 20 platinum atoms high and 14 platinum atoms wide, what is the mass (grams) of the atomic surface? c. If the atomic surface were changed to ruthenium atoms and the same surface mass as determined in part b is used, what number of ruthenium atoms is needed to construct the surface?
2.37 Why are empirical formulas preferred for describing polymer molecules?
1, A mineral sample is obtained from a region of the country that has high arsenic contamination. An elemental analysis yields the following elemental composition: Element Atomic Weight (g/mol) Percent Composition Zn 65.409 23.4% As 74.9216 53.7% O 15.9994 22.9% What is the empirical formula of this mineral? Group of answer choices ZnAsO4 Zn2AsO3 Zn2AsO4 ZnAs2O4 2.A mineral sample is obtained from a region of the country that has high arsenic contamination. An elemental analysis yields the following elemental composition: Element Atomic Weight (g/mol) Percent Composition Co 58.9332 21.2% Fe 55.845 6.71% As 74.9216 72.0% What is the empirical formula of this mineral? Group of answer choices Co3FeAs8 Co2FeAs8 Co8FeAs3 CoFe3As8 CoFeAs
5, A mineral sample is obtained from a region of the country that has high arsenic contamination. An elemental analysis yields the following elemental composition: Element Atomic Weight (g/mol) Percent Composition Cu 63.546 30.2% Zn 65.409 15.5% As 74.9216 23.7% S 32.065 30.5% What is the empirical formula of this mineral? Group of answer choices A, Cu6Zn3As4S12 B, Cu5Zn3As4S12 C, Cu6Zn3As4S10 D, Cu6Zn3As3S12 Cu3Zn6As4S12
Calculate the mass percent of Carbon (C) in Carbon dioxide (C02).A. 27.3% CB. 42% CC. 37.5% CD. 100% CReset SelectionMark for Review What’s This?
Manganese sulfate forms the hydrate MnSO4⋅?H2O(s)MnSO4⋅nH2O(s) . If this hydrate is heated to a high enough temperature, H2O(g)H2O(g) can be driven off, leaving MnSO4(s)MnSO4(s) . A 10.140 g10.140 g sample of the hydrate was heated to 300 ∘C300 ∘C . The resulting MnSO4(s)MnSO4(s) had a mass of 9.0592 g9.0592 g. Calculate the value of ?n in MnSO4⋅?H2O(s)MnSO4⋅nH2O(s) .
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