At 500 °C, hydrogen iodide decomposes according to 2HI(g) – --- H2(g)+l2(g) For HI(g) heated to 500 °C in a 1.00 L reaction vessel, chemical analysis determined these concentrations at equilibrium: [H2]=0.494 M , [12]=0.494 M, and [HI]=4.18 M . If an additional 1.00 mol of HI(g) is introduced into the reaction vessel, what are the equilibrium concentrations after the new equilibrium has been reached?

Chemistry for Engineering Students
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Author:Lawrence S. Brown, Tom Holme
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Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.35PAE: In the reaction in Exercise 12.33, another trial was carried out. The reaction began with an initial...
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At 500 °C, hydrogen iodide decomposes
according to
2HI(g) – --- H2(g)+l2(g)
For HI(g) heated to 500 °C in a 1.00 L
reaction vessel, chemical analysis
determined these concentrations at
equilibrium: [H2]=0.494 M , [12]=0.494 M,
and [HI]=4.18 M. If an additional 1.00 mol
of HI(g) is introduced into the reaction
vessel, what are the equilibrium
concentrations after the new equilibrium
has been reached?
Transcribed Image Text:At 500 °C, hydrogen iodide decomposes according to 2HI(g) – --- H2(g)+l2(g) For HI(g) heated to 500 °C in a 1.00 L reaction vessel, chemical analysis determined these concentrations at equilibrium: [H2]=0.494 M , [12]=0.494 M, and [HI]=4.18 M. If an additional 1.00 mol of HI(g) is introduced into the reaction vessel, what are the equilibrium concentrations after the new equilibrium has been reached?
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