Compound A has a molecular formula C9H18, and has the following; a. 3 secondary carbons b. 3 primary carbons C. 3 tertiary carbons d. A plane of symmetry Compound A is treated with Br2 and light to give an alkyl halide which was treated with strong base to form an alkene with two stereocenters (compound B). Compound B was treated with ozone and gave one product compound C with the formula C9H16O2.
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- Compound A (C9H12) absorbed 3 equivalents of H2 on catalytic reduction over apalladium catalyst to give B (C9H18). On ozonolysis, compound A produced 3 products, C, Dand E which was a ketone identified as cyclohexanone. On treatment with NaNH2 in NH3,followed by addition of iodomethane, compound A gave new hydrocarbon, F (C10H14). Drawstructures of A, B, C, D and F.Hydrogenation of alkene A with D2 in the presence of Pd-C affords a single product B. Keeping this result in mind, what compound is formed whenA is treated with each reagent: (a) mCPBA; (b) Br2, H2O followed by base? Explain these results.An optically active alkyne A (C10H14) can be catalytically hydrogenated to butylcyclohexane. Treatment of A with EtMgBr liberates no gas. Catalytic hydrogenation of A over Pd/C in the presence of quinoline poison and treatment of the product with O3 and then H2O2 gives an optically active tricarboxylic acid C8H12O6 (A tricarboxylic acids is a compound with three - CO2H groups.). Give the structure of A, and account for all observations.
- -Ocimene is a pleasant-smelling hydrocarbon found in the leaves of certain herbs. It has the molecular formula C10H16 and a UV absorption maximum at 232 nm. On hydrogenation with a palladium catalyst, 2,6-dimethyloctane is obtained. Ozonolysis of -ocimene, followed by treatment with zinc and acetic acid, produces the following four fragments: (a) How many double bonds does -ocimene have? (b) Is -ocimene conjugated or nonconjugated? (c) Propose a structure for -ocimene. (d) Write the reactions, showing starting material and products.Friedel–Crafts alkylation of benzene with (R)-2-chlorobutane and AlCl3 affords sec-butylbenzene.a. How many stereogenic centers are present in the product?b. Would you expect the product to exhibit optical activity? Explain, with reference to the mechanism.Write out all the isomers of the compound with molecular formula C4H10O Select the normal/ primaryisomer and treat it with conc. H2SO4 and heat. Identify the reaction and give the product ‘A’ from it. Treatment of ‘A’ with HCl/H2O gives ‘B’ Treatment of ‘A’ with cold KMnO4/ -OH gives ‘C’ Treatment of ‘A’ with Hot KMnO4/-OH gives ‘D’ followed by acidification of the mixture to give ‘E’
- Compound A, C11H16O, was found to be an optically active alcohol. Despite its apparent unsaturation, no hydrogen was absorbed on catalytic reduction over a Pd/C catalyst. On treatment of A with dilute H2SO4, dehydration occurred and an optically inactive alkene B, C11H14 was produced as the major product. Alkene B, on ozonolysis, gave two products. Product C, C7H6O, was shown to be an aldehyde while product D, C4H8O, was shown to be a ketone. Draw the structure of compound C. You do not have to consider stereochemistry. You do not have to explicitly draw H atoms. In cases where there is more than one answer, just draw one. HELP PLEASE I DONT UNDERSTAND THE PROCESSCompound A (C7H11Br) is treated with magnesium in ether to give B (C7H11MgBr), which reacts violently with D2O to give 1-methylcyclohexene with a deuterium atom on the methyl group (C). Reaction of B with acetone (CH3COCH3) followed by hydrolysis gives D (C10H18O). Heating D with concentrated H2 SO4 gives E (C10 H16), which decolorizes two equivalents of Br2 to give F (C10H16 Br4). E undergoes hydrogenation with excess H2 and a Pt catalyst to give isobutylcyclohexane. Determine the structures of compounds A through F, and show your reasoning throughout.Compound A (C7H11Br) is treated with magnesium in ether to give B (C7H11MgBr) which reacts violently with D2O to give 1-methylcyclohexene with a deuterium atom on the methyl group (C). Reaction of B with acetone (Ch3COCH3) followed by hydrolysis gives D (C10H18O). Heating D with concentrated H2SO4 gives E (C10H16), which reacts with 2 equivalents of Br2 to give F (C10H16Br4). E undergoes hydrogenation with excess H2 and Pt catalyst to give 2-methylpropylcyclohexane. Determine the structures of compounds A through F, and show your reasoning throughout.
- The spirocyclic pentadiene derivative F shown below is converted stereospecificallyinto compound G on heating. The transformation involves two consecutive pericyclicreactions of the same type, and proceeds via compound H which is not isolated. Identify the type of pericyclic reaction occurring, and determine the structure ofcompound H.Compound A has a molecular formula C6H12 , and has the following; 2 secondary carbons 2 primary carbons A plane of symmetry Compound A is treated with H2 and Pd to give compound B. Compound A was treated with ozone and gave 2 equivalents of compound C with the formula C3H6O.Compound A was then treated with CH2I2 and Zn to form Compound D, which has two stereocenters and is meso. What are the structures for compounds A-D? Compound A and Compound C IR spectrum are given below. What is the structure of Compound A?Compound A, C11H16O, was found to be an optically active alcohol. Despite its apparent unsaturation, no hydrogen was absorbed on catalytic reduction over a Pd/C catalyst. On treatment of A with dilute H2SO4, dehydration occurred and an optically inactive alkene B, C11H14 was produced as the major product. Alkene B, on ozonolysis, gave two products. Product C, C8H8O, was shown to be a methyl ketone while product D, C3H6O, was shown to be an aldehyde.