Compound A: ЗН 100 1H NMR of A IR (A] 8. 6. 4000 3500 3000 2500 2000 1500 1000 500 ppm Wavenumber (cm) Compound B: 100 'H NMR of B IR (B) 1H 50- very broad singlet 12 10 4000 3500 3000 2500 2000 1500 1000 500 ppm Wavenumber (cm") % Transmittance % Transmitance

Compound A: ЗН 100 1H NMR of A IR (A] 8. 6. 4000 3500 3000 2500 2000 1500 1000 500 ppm Wavenumber (cm) Compound B: 100 'H NMR of B IR (B) 1H 50- very broad singlet 12 10 4000 3500 3000 2500 2000 1500 1000 500 ppm Wavenumber (cm") % Transmittance % Transmitance

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

ChapterL3: Carbon (13c) Nmr Spectroscopy

Section: Chapter Questions

Problem 8E

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Concept explainers

NMR Spectroscopy

NMR stands for Nuclear Magnetic Resonance in which the study of different molecules is done based on the interaction of radiofrequency electromagnetic radiations with the nuclei of molecules placed in a strong magnetic field. A precise study of spectra of visible light and all bands of electromagnetic radiation is called spectroscopy.

Question

Use the 1H NMR and IR spectra given below to identify the structures of two isomers (A and B) having molecular formula C4H8O2.

Compound A:
ЗН
100
1H NMR of A
IR (A]
8.
6.
4000 3500
3000
2500
2000
1500
1000
500
ppm
Wavenumber (cm)
Compound B:
100
'H NMR of B
IR (B)
1H
50-
very broad
singlet
12
10
4000
3500
3000
2500
2000
1500
1000
500
ppm
Wavenumber (cm")
% Transmittance
% Transmitance

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