Compute a 3-month weighted average forecast for months 4 through 9. Assign weights of 0.55, 0.33 and 0.12 to the months in sequence, starting with the most recent month. Compare the two forecasts using MAD. Which forecast is better the 3-month moving average or the 3-month weighted moving average and why?
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Compute a 3-month weighted average
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- RJ produces chocolate balls. There are five samples, and each sample contains 4 packs of chocolate balls that were randomly selected and weighed. The following is the sample data: Weight (lb) Sample 1 Sample 2 Sample 3 Sample 4 Sample 5 Pack 1 0.94 1 1.05 0.98 0.93 Pack 2 1.15 0.93 1.13 0.93 0.8 Pack 3 0.88 1 1.07 0.9 1.12 Pack 4 0.96 1.06 0.97 0.89 1.01 Suppose the standard deviation is unknown, and the X-bar chart is based on 3-sigma limits. Based on the sample data, what is LCL? a 0.920 b 0.887 c 0.816 d 0.844Accountants at the Tucson firm, Larry Youdelman,CPAs, believed that several traveling executives were submittingunusually high travel vouchers when they returned from businesstrips. First, they took a sample of 200 vo uchers submitted fromthe past year. Then they developed the following multiple regressionequation relating expected travel cost to number of days onthe road (x1) and distance traveled (x2) in miles:y = $90.00 + $48.50x1 + $.40x2The coefficient of correlation computed was .68.a) If Barba ra Downey returns from a 300-miJe trip that took herout of town for 5 days, what is the expected amount she shouldclaim as expenses?b) Downey submitted a reimbursement request for $685. Whatshould the accountant do?c) Should any other variables be included? Which ones? Why?Let’s suppose that you have a set of time-series variables, and you want to model the relationship between them. Read the situations given below and answer the questions. (200 words)a) Explain the statistical test if the linear combination (of time-series variables) is I(0).b) Which statistical test can be applied if all the series are integrated of the same order I(1). Justify your answer
- The chart below is a summary of the main results of a test data set representing the population observed purchasing a virtual digital assistant. What does the accuracy rate indicate? Metrics Metric Value Accuracy (#correct) 178 Accuracy (%correct) 85.6 Specificity 0.88219 Sensitivity (Recall) 0.6 Precision 0.82400 F1 Score 0.88213 Success Class 1 Success Probability 0.4 Multiple Choice 85.6% of the population has purchased a virtual assistant. 60% of the observations are correctly classified. 85.6% of the observations are correctly classified. 14.4% of the observations are correctly classified. Explain all the incorrect answers alsoA gaming company develops different game packages that are downloadable from their servers on the internet. They need to make sure the download speed of their servers is as planned and adjust the capacity of their servers anytime needed. They measure the download time of their software 6 times a day for 5 days as shown in the table below. The standard deviation of the download time is 4.5. Download time in seconds Day 1 Day 2 Day 3 Day 4 Day 5 41 41 37 36 37 44 45 46 39 39 43 45 45 40 40 45 42 46 41 39 43 46 39 38 42 46 43 41 42 38 a. Construct an appropriate control chart (with two-sigma limits) to demonstrate if the download time is within the company’s expectation and the process is in control. (Round your answer to two decimal places.)Rajan wanted a radio from Jacky's. It appears that Rajan is particularly interested in purchasing a Radio from the inexpensive retailer's sales manager for consumer electronics. He tells Jacky, the salesperson at the inexpensive store where he thinks he'll get the best deal, that his old radio died and he wants to listen to his favourite tunes. He wants a replacement radio as quickly as possible. In three and a half weeks, Rajan's favourite model will be 10% off.He suspects Rajan won't wait and will find another job. Jacky will earn less on the lowered price. He thinks that telling Rajan of the sale makes little sense.When Jacky tells Rajan that the radio set he wants is no longer available and won't be for another week, Rajan is enraged. Fearing losing the business, Jacky begs his sales manager, Michelle, to speed up delivery. Michelle says it's impossible and suggests Jacky tell Rajan the store can get the set in 24 hours and sell him the demo model. Michelle says the sample is new…
- The human resource manager at a car dealership wants to know if the ages of its employees are related to the department that they work in. Data was compiled and tabulated in a 2-way contingency table. The employees were classified according to their age and department.Expected counts are printed below observed countsSales Accounts Marketing RepairsTotal20-29 8 10 27 43 8817.74 *** 26.20 23.6230-39 29 26 38 22 *23.18 26.72 34.24 30.8640-49 33 32 72 82 21944.15 50.88 65.20 58.7750-59 81 106 86 54 32765.92 75.97 97.36 87.75Total 151 ** 223 201 749Chi-Sq = 5.348 + **** + 0.024 + 15.912 + 1.459 + 0.019 + 0.413 + 2.544 +2.816 + 7.003 + 0.709 + 9.182 + 3.448 + 11.875 + 1.325 + 12.983 = 80.395DF = *****, P-Value = ******No cells with expected counts less than 5.a) Name the random variables present in the table above. b) Carefully define the null and alternative hypotheses of the Chi Square test underlying the generation of the above table. c) Fill in the gaps marked by ‘*’, ‘**’, ‘***’, ‘****’…Given the attached data. Answer the following questions for a 7 period moving average. t At 1 5477 2 3338 3 4799 4 2852 5 6332 6 8385 7 4382 8 4184 9 14229 10 10385 11 11676 12 5271 13 8938 14 9279 15 13990 16 2890 17 13027 18 8970 19 6700 20 7065 21 12491 22 8748 23 8396 24 6102 25 7559 26 7997 27 11981 28 10680 29 5783 30 2501 31 7620 32 10194 33 7908 34 11985 35 5863 36 3024 37 8758 38 1640 39 6569 40 11728 41 6659 42 2830 43 10018 44 8448 45 12409 46 2083 47 6374 48 7438 49 4576 50 4795 MAD = Average(|A-F|) TS =SUM(A-F)/MAD MSE = Average(A-F)2 1. Compute your forecast for period 51. The potential answers are: A: 11221.6 units. B: 12461 units. C: 8020.83 units. D: 4414 units. E: 6589 units.Each of these columns of data represent a different soda bottling line, with the values representing the amount of soda per bottle in ounces. The business question being asked for each of the three comparisons is "do the two bottling lines bottle the same volume of soda on average, bearing in mind that the sample difference that you may observe could just be coincidence." What is the null hypotheses? Alternative hypothesis P value Alpha=0.05 Is it significant ? t-Test: Two-Sample Assuming Unequal Variances C7 C8 Mean 20.01679499870 20.59290905613 Variance 0.01032479977 0.01011215081 Observations 50.00000000000 50.00000000000 Hypothesized Mean Difference 0.00000000000 df 98.00000000000 t Stat 28.49610006164 P(T<=t) one-tail 0.00000000000 t Critical one-tail 1.66055121707 P(T<=t) two-tail 0.00000000000 t Critical two-tail 1.98446745451