Computer Science Suppose for a processor system it takes 35 cycles to push and pop registers onto the stack and change the PC value to the start of the interrupt service routine (ISR) or return from it. Suppose also that the ISR software takes additional 45 cycles to store the process state before the actual ISR body begins its work, and suppose it takes the same number of cycles to restore the process state when ISR is finished. If the ISR body takes 1000 cycles, what is the percent total overhead every time the ISR is executed? If the processor is running at a 2 GHz clock frequency, how long does it take before the ISR body begins execution in nanoseconds? This is usually called the ISR latency

Computer Science Suppose for a processor system it takes 35 cycles to push and pop registers onto the stack and change the PC value to the start of the interrupt service routine (ISR) or return from it. Suppose also that the ISR software takes additional 45 cycles to store the process state before the actual ISR body begins its work, and suppose it takes the same number of cycles to restore the process state when ISR is finished. If the ISR body takes 1000 cycles, what is the percent total overhead every time the ISR is executed? If the processor is running at a 2 GHz clock frequency, how long does it take before the ISR body begins execution in nanoseconds? This is usually called the ISR latency

Systems Architecture

7th Edition

ISBN:9781305080195

Author:Stephen D. Burd

Publisher:Stephen D. Burd

Chapter4: Processor Technology And Architecture

Section: Chapter Questions

Problem 3PE: Processor R is a 64-bit RISC processor with a 2 GHz clock rate. The average instruction requires one...

See similar textbooks

Computer Science

Suppose for a processor system it takes 35 cycles to push and pop registers onto the stack and change the PC value to the start of the interrupt service routine (ISR) or return from it. Suppose also that the ISR software takes additional 45 cycles to store the process state before the actual ISR body begins its work, and suppose it takes the same number of cycles to restore the process state when ISR is finished. If the ISR body takes 1000 cycles, what is the percent total overhead every time the ISR is executed? If the processor is running at a 2 GHz clock frequency, how long does it take before the ISR body begins execution in nanoseconds? This is usually called the ISR latency

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.

Similar questions

Processor R is a 64-bit RISC processor with a 2 GHz clock rate. The average instruction requires one cycle to complete, assuming zero wait state memory accesses. Processor C is a CISC processor with a 1.8 GHz clock rate. The average simple instruction requires one cycle to complete, assuming zero wait state memory accesses. The average complex instruction requires two cycles to complete, assuming zero wait state memory accesses. Processor R can’t directly implement the complex processing instructions of Processor C. Executing an equivalent set of simple instructions requires an average of three cycles to complete, assuming zero wait state memory accesses. Program S contains nothing but simple instructions. Program C executes 70% simple instructions and 30% complex instructions. Which processor will execute program S more quickly? Which processor will execute program C more quickly? At what percentage of complex instructions will the performance of the two processors be equal?
Consider a system which employs an interrupt driven I/O for a particular device that transfer data at an average of 10 KBps on a continuous basis. Assume that interrupt processing takes about 100 µs (i.e. jump to the interrupt service routine (ISR); execute it and return to the main program). The fraction of processor time which is consumed by this I/O device when it is interrupted for every byte will be ?
When a central processing unit (CPU) produces an interrupt, the processor is compelled to stop whatever it is working on in order to react to the signal that has been received. It has piqued my interest to learn more about the reasoning for pausing the procedure in order to finish the assignment. Let's begin by going through the steps involved in the process of interrupting, and then we'll move on to the steps involved in the process of executing. Explain?
3. An external event is sensed using polling with period P. It takes 100 cycles to processthe event. Processor frequency is 48 MHz. Before starting a new period, the previouspolling task should have finished. The relative deadline for processing an event is 10μs.(a) Determine the range of feasible polling periods? (b) Suppose now that an unrelated interrupt may occur and the interrupt has higher priority than the code for processing the polling event. Including all overhead, it takes 40 cycles to process the interrupt. The minimum time between two subsequent interrupts is T. Suppose that T is larger than 140 cycles. Determine the range of feasible polling periods.
Please explain how prioritizing the I/O queue above the process execution queue might improve performance. If the I/O is interrupted, who knows what will happen. To what extent this will reduce the maximum burst rate of the CPU is unclear. I don't think I understand what you're getting at.
Because of this, the CPU suspends any currently executing processes until the interrupt has been resolved. Interrupt service is the term used to describe this. What is the rationale for halting the procedure that is presently in progress? Isn't it possible, as an alternative, to just finish the presently operating operation and deal with the interruption afterward?
As soon as an interrupt is received, the CPU suspends the process that is presently running and continues to serve the interrupted process. Justification for suspending an already-running procedure As an alternative, why can't we just complete the currently running process and deal with the interrupt afterwards?
If interrupt synchronization is turned off, it must be turned back on before leaving a critical section. For the sake of argument, let's say that one CPU disables interrupts as it reaches a critical section, while another CPU has its interrupt enable flag set to 0. P2 needs access to the crucial area and is willing to utilize any of the two CPUs available. Consider the consequences that are even somewhat feasible.
Consider a paging system where the page table is stored in fast access registers (TLB) with an access time of 10 nanoseconds and a hit ratio of 80%. Memory access time is 100 nanoseconds (only one memory access). Assume that when a process generates a page fault, one of the processes pages currently in main memory will have to be replaced and that 60% of the time the page to be replaced has been modified. Assume that it takes 20 milliseconds to service a page fault if the page to be replaced has been modified and 10 milliseconds if it has not been modified. What is the page fault rate for an effective memory access time of 240 nanoseconds? Explain your steps and calculations.
A processor can decode encrypted data and system instructions in a number of different ways, and it can also execute instructions based on data that has been decoded and system instructions that have already been performed in a number of different ways. The rebuttals that have been sent in will be encrypted before the processor reads them. Is there any benefit to use a CPU in such a manner if at all possible? What are the system requirements, and how do they compare to the system's performance and efficiency?
Given the following set of events, show which routines the CPU is executing for times 0 to 150 ms. Each handler routine (with its interrupt request) takes 25 ms to complete. The priority of the interrupts ranges from IRQ6 as the highest priority interrupt to IRQ0 as the lowest priority Time Action 0 ms Start of main program 10 ms IRQ1 25 ms IRQ2 35 ms IRQ5 45 ms IRQ6 55 ms IRQ4 Time Action 0 ms: Start of Main Program 10 ms: IRQ1 .. ms …….
An interrupt from a CPU causes the processor to halt what it is doing and react to the signal received from the interrupt source. In order to finish this work, why should the operation be stopped? Let's start with the process of interrupting, and then go on to the process of executing the interrupting. explain?