For the reversible reactionN2(g)+O2(g)2NO(g)the concentrations at equilibrium are [N2] = 0.17 M and [O2] = 0.44 M, and K = 2.1 × 10–3. Find [NO] at equilibrium.

Answered: concentrations at equilibrium

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter12: Chemical Equilibrium

Section12.5: Using Equilibrium Constants

Problem 12.5PSP: For the equilibrium 2 SO2(g) + O2(g) 2 SO3(g) Kc = 245 (at 1000 K) the equilibrium concentrations...

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For the reversible reaction

N2(g)+O2(g)2NO(g)

the concentrations at equilibrium are [N₂] = 0.17 M and [O₂] = 0.44 M, and K = 2.1 × 10^–3. Find [NO] at equilibrium.

Expert Solution

Step 1

Equilibrium constant for any reaction at equilibrium is the ratio of product of concentrations of product side to product of concentration at reactant side raised to power of molecules in which react.

For the given reaction,

N₂(g) + O₂(g) $\to$ 2NO(g)

Value of K = [NO]² / [N₂]*[O2]

As we know K is a ratio of 2 similar quantities, therefore it is a unitless quantity.

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