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2. Consider the reaction CO(g)CH3OH(g)2H2(g)A reaction mixture in a 1.00L flask initially only contains 0.185 mol of CO and 0.225mol of H2. At equilibrium, 0.0521 mol CH3OH have formed. Calculate the equilibriumconstant Keq for this reaction

Question
2. Consider the reaction CO(g)
CH3OH(g)
2H2(g)
A reaction mixture in a 1.00L flask initially only contains 0.185 mol of CO and 0.225
mol of H2. At equilibrium, 0.0521 mol CH3OH have formed. Calculate the equilibrium
constant Keq for this reaction
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2. Consider the reaction CO(g) CH3OH(g) 2H2(g) A reaction mixture in a 1.00L flask initially only contains 0.185 mol of CO and 0.225 mol of H2. At equilibrium, 0.0521 mol CH3OH have formed. Calculate the equilibrium constant Keq for this reaction

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Step 1

Initial concentration of CO and H2 and also the concentration of CH3OH at equilibrium can be determined using the formula for molarity.

0.185 mol
No. of moles
0,185 M
Initial concentration of CO
Volume
1.0 L
0.225 mol
Initial concentration of H
0.225 M
1.0 L
0.0521 mol
Concentration of CH OH at equilibrium
0.0521 M
1.0 L
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0.185 mol No. of moles 0,185 M Initial concentration of CO Volume 1.0 L 0.225 mol Initial concentration of H 0.225 M 1.0 L 0.0521 mol Concentration of CH OH at equilibrium 0.0521 M 1.0 L

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Step 2

The concentration of each reactant at equilibrium ca...

СО +
2 Н,
CH,ОН
Initial
0.185
0.225
0
Change
-2x
x
-X
Equilibrium 0.185-x)(0.225 - 2x) 0.0521
x = 0.0521
Therefore,
[сH,оН] — 0.0521 м
CO(0.185-0.0521) M 0.1329 M
[H2] (0.225-(2x0.0521)) M 0.1208 M
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СО + 2 Н, CH,ОН Initial 0.185 0.225 0 Change -2x x -X Equilibrium 0.185-x)(0.225 - 2x) 0.0521 x = 0.0521 Therefore, [сH,оН] — 0.0521 м CO(0.185-0.0521) M 0.1329 M [H2] (0.225-(2x0.0521)) M 0.1208 M

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Equilibrium Concepts

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