Consider a place where the gravity is 4 times the gravity on Earth (g' = 4g), then the frequency of oscillation of a simple pendulum in that place, f', as compared to its frequency on earth is: O f = f/2 O f' = 9f O f' = 4f O f' = 2f O f' = f/3

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Chapter13: Vibrations And Waves
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Problem 32P: A spring of negligible mass stretches 3.00 cm from its relaxed length when a force of 7.50 N is...
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Consider a place where the gravity is 4
times the gravity on Earth (g' = 4g), then the
frequency of oscillation of a simple
pendulum in that place, f', as compared to
its frequency on earth is:
f' = f/2
f' = 9f
f' = 4f
f' = 2f
f' = f/3
A simple pendulum consists of a 0.8-kg bob
connected to a massless inextensible cord
with a lengthL = 1.4 m. The bob is set into
motion and its angular displacement is
given by e(t) = 0.11cos(wt), where e is in
radians and t is in seconds. Take g = 9.8
m/s^2, determine the mechanical energy of
this pendulum.
0.090 J
0.066 J
Transcribed Image Text:4:30 1 Classroom a docs.google.com 3 sec 1.5 sec Consider a place where the gravity is 4 times the gravity on Earth (g' = 4g), then the frequency of oscillation of a simple pendulum in that place, f', as compared to its frequency on earth is: f' = f/2 f' = 9f f' = 4f f' = 2f f' = f/3 A simple pendulum consists of a 0.8-kg bob connected to a massless inextensible cord with a lengthL = 1.4 m. The bob is set into motion and its angular displacement is given by e(t) = 0.11cos(wt), where e is in radians and t is in seconds. Take g = 9.8 m/s^2, determine the mechanical energy of this pendulum. 0.090 J 0.066 J
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