Consider a place where the gravity is %3D 4 times the gravity on Earth (g' = 4g), then the frequency of oscillation of a simple pendulum in that place, f', as compared to its frequency on earth is: O f' = f/3 O f' = 9f f' = 2f f' = f/2

Consider a place where the gravity is %3D 4 times the gravity on Earth (g' = 4g), then the frequency of oscillation of a simple pendulum in that place, f', as compared to its frequency on earth is: O f' = f/3 O f' = 9f f' = 2f f' = f/2

Name: .6v3ft m/Consider a place where the gravity is4 times the gravity on
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Description: .6v3ft m/Consider a place where the gravity is4 times the gravity on Earth (g' = 4g),then the frequency of oscillation of asimple pendulum in that place, f', ascompared to its frequency on earthis:f' = f/3O f' = 9ff' = 2fO f' = f/2O f' = 4f

Physics for Scientists and Engineers

10th Edition

ISBN:9781337553278

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter15: Oscillatory Motion

Section: Chapter Questions

Problem 17P: A simple pendulum makes 120 complete oscillations in 3.00 min at a location where g = 9.80 m/s2....

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