Consider a situation where you have a parental cross with the mother and father phenotypes listed below The counts of the F1 offspring are listed in Table 1. Two randomly selected individuals are selected and mated to produce a set of F2 individuals. If you test the F2 counts to determine whether they are consistent with an autosomal dominant mode of inheritance, what is your decision? Use a 0.05 significance level. PARENTAL CROSS Parental cross: Mother with disease phenotype, Father with wild-type phenotype. Table 1. F1 DATA Gender Phenotype Disease Wild-Type Male 0 23 Female 0 34 Table 2. F2 DATA Gender Phenotype Disease Wild-Type Male 7 25 Female 0 25 a) Do not reject the null hypothesis that the F2 data are consistent with an autosomal dominant mode of inheritance; chi-square goodness of fit test p-value is greater than 0.05. b) Do not reject the null hypothesis that the F2 data are consistent with an autosomal dominant mode of inheritance; chi-square goodness of fit test statistic value is between 0 and 1. c) Reject the null hypothesis that the F2 data are consistent with an autosomal dominant mode of inheritance; the p-value for the chi-square goodness of fit test is less than 0.05. d) Reject the null hypothesis that the F2 data are consistent with an autosomal dominant mode of inheritance; the p-value for the chi-square goodness of fit test is greater than 0.05. e) Reject the null hypothesis that the F2 data are consistent with an autosomal dominant mode of inheritance; chi-square goodness of fit test p-value is 1e-06.
Consider a situation where you have a parental cross with the mother and father
The counts of the F1 offspring are listed in Table 1. Two randomly selected individuals are selected and mated to produce a set of F2 individuals. If you test the F2 counts to determine whether they are consistent with an autosomal dominant mode of inheritance, what is your decision? Use a 0.05 significance level.
PARENTAL CROSS
Parental cross: Mother with disease phenotype, Father with wild-type phenotype.
Table 1. F1 DATA
Gender | Phenotype | ||
Disease | Wild-Type | ||
Male | 0 | 23 | |
Female | 0 | 34 |
Table 2. F2 DATA
Gender | Phenotype | ||
Disease | Wild-Type | ||
Male | 7 | 25 | |
Female | 0 | 25 |
a) Do not reject the null hypothesis that the F2 data are consistent with an autosomal dominant mode of inheritance; chi-square goodness of fit test p-value is greater than 0.05.
b) Do not reject the null hypothesis that the F2 data are consistent with an autosomal dominant mode of inheritance; chi-square goodness of fit test statistic value is between 0 and 1.
c) Reject the null hypothesis that the F2 data are consistent with an autosomal dominant mode of inheritance; the p-value for the chi-square goodness of fit test is less than 0.05.
d) Reject the null hypothesis that the F2 data are consistent with an autosomal dominant mode of inheritance; the p-value for the chi-square goodness of fit test is greater than 0.05.
e) Reject the null hypothesis that the F2 data are consistent with an autosomal dominant mode of inheritance; chi-square goodness of fit test p-value is 1e-06.
Trending now
This is a popular solution!
Step by step
Solved in 4 steps