Consider an aircraft in a maneuver. At an instant in time, the angular velocity of the aircraft relative to Earth is ū = 1.8b1+0.57b2+0.21b3, the velocity of the center of mass of the aircraft relative to Earth is i = 25b1 +10b2+8b3, the angular acceleration of the aircraft relative to Earth is a = 0.26b1 +0.1b2+0.05b3, and the acceleration of the center of mass of the aircraft relative to Earth is a = 2b1 +5b2+7b3. What is the magnitude of the velocity at a point on the aircraft whose position vector relative to the center of mass is 7 = 6b1+3b2+6b3. Note b1, b2, b3 are unit vectors fixed in the aircraft reference frame.

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Consider an aircraft in a maneuver. At an instant in time, the angular velocity of the aircraft relative
to Earth is i = 1.8b1 +0.57b,+0.21b3, the velocity of the center of mass of the aircraft relative to
Earth is i = 25b1 +10bz+8b3, the angular acceleration of the aircraft relative to Earth is a = 0.26b1
+0.1b2+0.05 b3, and the acceleration of the center of mass of the aircraft relative to Earth is a = 2b1
+5b2+7b3. What is the magnitude of the velocity at a point on the aircraft whose position vector
relative to the center of mass is 7 = 6b1+3b2+6b3.
Note b1, b2, bz are unit vectors fixed in the aircraft reference frame.
Transcribed Image Text:Consider an aircraft in a maneuver. At an instant in time, the angular velocity of the aircraft relative to Earth is i = 1.8b1 +0.57b,+0.21b3, the velocity of the center of mass of the aircraft relative to Earth is i = 25b1 +10bz+8b3, the angular acceleration of the aircraft relative to Earth is a = 0.26b1 +0.1b2+0.05 b3, and the acceleration of the center of mass of the aircraft relative to Earth is a = 2b1 +5b2+7b3. What is the magnitude of the velocity at a point on the aircraft whose position vector relative to the center of mass is 7 = 6b1+3b2+6b3. Note b1, b2, bz are unit vectors fixed in the aircraft reference frame.
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