Consider that titration of 30.0 ml of 0.265m weak base B (Kb = 1.3×10^-10) with 0.150M HI. a) What would be the pH of the solution after the addition of 20.0 mL of HI b) How many mL of HI would be required to reach the halfway point

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter15: Additional Aqueous Equilibria
Section: Chapter Questions
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Consider that titration of 30.0 ml of 0.265m weak base B (Kb = 1.3×10^-10) with 0.150M HI. a) What would be the pH of the solution after the addition of 20.0 mL of HI b) How many mL of HI would be required to reach the halfway point
Expert Solution
Step 1

Given:

Volume of the weak base = 30.0 mL

Concentration of the base = 0.265 M

Concentration of HI = 0.150 M

Kb = 1.3×10-10

Therefore, calculating pKb as:

pKb = -log10Kb= -log101.3×10-10= 9.886

 

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