Consider the circuit shown. If you were to solve for the unknown currents using Kirchhoff’s rules, what is the least number of junctions that need to be evaluated? Choose the best answer. One Two Four Six Circuit cannot be evaluated using Kirchhoff’s rules

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Consider the circuit shown. If you were to solve for the unknown currents using Kirchhoff’s rules, what is the least number of junctions that need to be evaluated? Choose the best answer.

One

Two

Four

Six

Circuit cannot be evaluated using Kirchhoff’s rules

R = 20 N
R3 = 8N
a
b
12
1= 0.52
R2 = 6N
E2
= 3.0 V
Ezi= 12 V
13:= 0.5 2
E= 18|v
12 0.25 2E
E 18 V
+1
f Ra 15 2 e
= 0.75 2
Transcribed Image Text:R = 20 N R3 = 8N a b 12 1= 0.52 R2 = 6N E2 = 3.0 V Ezi= 12 V 13:= 0.5 2 E= 18|v 12 0.25 2E E 18 V +1 f Ra 15 2 e = 0.75 2
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