Consider the code in the clear_one function. void clear_one (int m[N] [N][N]) int i, j, k; for (i = 0; i < N; i++) for (j = 0; j < N; j++) for (k = 0; k < N; k++) m[i] [5] [k] - 0; %3D What type of reference pattern does the clear_one function have?
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Computer Architecture Question, please do not copy your answers from chegg, they are wrong and I will down vote you.
![Consider the code in the clear_one function.
void clear_one (int m[N] [N] [N])
int i, j, k;
for (i = 0; i < N; i++)
for (j = 0; j < N; j++)
for (k = 0; k < N; k++)
m[i][j] [x] = 0;
}
What type of reference pattern does the clear_one function have?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0ac06df2-2a9c-40c9-806b-1fda8ac47c54%2Fc5538d40-99e5-4898-9983-9bc87cdf31a7%2Fmb7axl_processed.png&w=3840&q=75)
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- Write a function in c programming language that gets an array of points ( function is defined as : typedef struct{ int x; Int y; } point; ) and sorts the array using qsort().Given two points a=(ax,ay) and b=(bx,by) we compare them as follows: 1) if (ax)2+(ay)2 < (bx)2+(by)2, then a should come before b in the sorted array. 2) if (ax)2+(ay)2 = (bx)2+(by)2, then we compare the points by the x coordinate. Remark: For a point a=(ax,ay) the quantity ((ax)2+(ay)2)1⁄2 is the distance of a from the (0,0). That is, we sort the points according to their distance to (0,0), and if for points at the same distance, then we sort them according to the first coordinate. You will need to implement the comparison function, and apply qsort() on the array with this comparison function. For example: - Input: [(3,2), (7,1), (1,1), (3,4), (5,0), (7,1)] - Expected output: [(1,1), (3,2), (3,4), (5,0), (7,1), (7,1) ] Explanation:(1,1) is first because 12+12=2 is the smallest(3,2)…Write the following three functions in c programming language: a) The function gets an array A of length n of ints, and a boolean predicate pred. It returns the smallest index i such that pred(A[i])==true.If no such element is not found, the function returns -1.int find(int* A, int n, bool (*pred)(int)); b) The function gets an array A of length n of ints, and a function f. It applies f to each element of A.void map(int* A, int n, int (*f)(int)); c) The function gets an array A of length n of ints, and a function f. The function f gets 2 ints and works as follows: Start with accumulator = A[0] For i=1...length-1 compute accumulator=f(accumulator, A[i]) Return accumulator For example, if f computes the sum of the two inputs, then reduce() will compute the sum of the entire array.int reduce(int* A, int n, int (*f)(int,int));IN C Programing Let us define the weighted sum of an integer array a[0], a[1], a[2], …, a[n-1] be a[0]*1 + a[1]*2 + a[2]*3 + …+a[n-1]*n. For example, the weighted sum of the array [5,2,6] would be 5*1+2*2+6*3 = 27. Write a recursive function that takes in an array numbers and its length n, and returns its weighter sum. You can assume n is non-negative integer. int weightedSum(int numbers[], int n) {
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