Consider the differential equation: xy" – y' 18y (1) Making the changes of variable x= e', y= u(t)e-2t in the differential equation (1), the differential equation u is obtained, depending on t, given by: u" - 6u' - 10u = 0. The solution of the differential equation (1), depending on the parameter t, with constant cl and c2, is given by: et S2(t) %3D O a) y(t) et 19 %3D S¤(t) et %3D Ob) y(t) e* (c1 cos(t/19) + c2 sen(tv/19)) S2(t) c) y(t) et '+cze tv19) C2e et d) Į #(t) y(t) e' (c, cos(tv/19) + C2 sen(tv/19))

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