Consider the element vanadium (Z=23)a) There is a line in the vanadium spectrum at 318.5nm.i. What is the frequency of the line?ii. What is the energy difference between the two levels responsible for this line in kJ per mole?iv. The ionization energy of vanadium from the ground state is 650.2 kJ/mol. Assume that the transition in (3) is from the ground state to an excited state. If that is the case, calculate the ionization energy from the excited state.

Question
Asked Sep 30, 2019
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Consider the element vanadium (Z=23)
a) There is a line in the vanadium spectrum at 318.5nm.

i. What is the frequency of the line?
ii. What is the energy difference between the two levels responsible for this line in kJ per mole?
iv. The ionization energy of vanadium from the ground state is 650.2 kJ/mol. Assume that the transition in (3) is from the ground state to an excited state. If that is the case, calculate the ionization energy from the excited state.

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Expert Answer

Step 1

(i)The frequency of the line at given wavelength 318.5nm can be calculated as

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v 3x10 ms3 318.5x10 m -9.41x1014Hz

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Step 2

(ii)The energy difference between two ...

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E hv (6.626x1034)x(9.41x10) -62.35x1020 -62.35x102 kJ mole 6.023x1023 energy per mole=6.023x102 x62.35x1023 375.53KJ/mol

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