Consider the energy levels for a hydrogen atom, listed in the table below. Each energy represents what is required for the negatively charged electron to escape. For example, if the electron were in the n =1 level, it would need to gain 13.6 electron volts in order to escape the attraction of the atomic nucleus. Note: an electron infinitely far from the proton is said to have zero potential energy; any closer, andits potential energy is said to be negative.Level (n =)1E =2hcλ3456Energy (in eV)-13.6-3.40-1.51-0.850(a) What energy (in eV) would a photon have, if it were emitted when an electron dropped from the n = 5 level to n = 4?eVHz-0.544(b) The equation for a photon's energy can be written:-0.378Since we know that for lightwhere h is known as Planck's constant and is equal to 4.136 x 10-15 eV s. (Note that h has a different numerical value in SI units.)с= f, we can rewrite the equation for the energy of a photon as E = h.f.AWhat, then, is the frequency (in Hz) of the photon from your answer to part (a)? (c) What region of the electromagnetic spectrum does this correspond to? (Refer to the frequency range chart for the EM spectrum below.)EM SpectralRegionFrequency(Hz)Radio<3 x 10⁹3 x 10⁹ to 3 x 10123 x 10¹2 to 4.3 x 10144.3 x 10¹4 to 7.5 x 10¹47.5 x 10¹4 to 3 x 10¹63 x 10¹6 to 3 x 101⁹> 3 x 10¹9MicrowaveInfraredVisibleUltravioletX-raysGamma raysradiomicrowaveinfraredvisibleultravioletO x-raysO gamma raysWavelength(angstroms)> 10⁹10⁹ to 106106 to 7,0007,000 to 4,0004,000 to 100100 to 0.1< 0.1

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Consider the energy levels for a hydrogen atom, listed in the table below. Each energy represents what is required for the negatively charged electron to escape. For example, if the electron were in the n = 1 level, it would need to gain 13.6 electron volts in order to escape the attraction of the atomic nucleus. Note: an electron infinitely far from the proton is said to have zero potential energy; any closer, and its potential energy is said to be negative. Energy (in eV) Level (n =) 1 E = 3 hc λ 4 5 6 -13.6 -3.40 -1.51 -0.850 (a) What energy (in eV) would a photon have, if it were emitted when an electron dropped from the n = 5 level to n = 4? eV Hz -0.544 (b) The equation for a photon's energy can be written: -0.378 where h is known as Planck's constant and is equal to 4.136 x 10-15 eV s. (Note that h has a different numerical value in SI units.) с Since we know that for light = f, we can rewrite the equation for the energy of a photon as E = h. f. A What, then, is the frequency (in Hz) of the photon from your answer to part (a)?

Consider the energy levels for a hydrogen atom, listed in the table below. Each energy represents what is required for the negatively charged electron to escape. For example, if the electron were in the n = 1 level, it would need to gain 13.6 electron volts in order to escape the attraction of the atomic nucleus. Note: an electron infinitely far from the proton is said to have zero potential energy; any closer, and its potential energy is said to be negative. Energy (in eV) Level (n =) 1 E = 3 hc λ 4 5 6 -13.6 -3.40 -1.51 -0.850 (a) What energy (in eV) would a photon have, if it were emitted when an electron dropped from the n = 5 level to n = 4? eV Hz -0.544 (b) The equation for a photon's energy can be written: -0.378 where h is known as Planck's constant and is equal to 4.136 x 10-15 eV s. (Note that h has a different numerical value in SI units.) с Since we know that for light = f, we can rewrite the equation for the energy of a photon as E = h. f. A What, then, is the frequency (in Hz) of the photon from your answer to part (a)?

Modern Physics

3rd Edition

ISBN:9781111794378

Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer

Publisher:Raymond A. Serway, Clement J. Moses, Curt A. Moyer

Chapter4: The Particle Nature Of Matter

Section: Chapter Questions

Problem 31P

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