Consider the equilibrium of PbCl2(s) in water. PbCl2(s) ↔↔ Pb2+(aq) + 2Cl-(aq) What is the effect of adding NaCl(aq) to the equilibrium solution? a. The sodium ion reduces the Pb2+ to Pb(s). b. PbCl2 solubility increases due to the common-ion effect. c. PbNa2(s) precipitates. d. The NaCl(aq) has no effect on
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Consider the equilibrium of PbCl2(s) in water.
PbCl2(s) ↔↔ Pb2+(aq) + 2Cl-(aq)
What is the effect of adding NaCl(aq) to the equilibrium solution?
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a. |
The sodium ion reduces the Pb2+ to Pb(s). |
|
b. |
PbCl2 solubility increases due to the common-ion effect. |
|
c. |
PbNa2(s) precipitates. |
|
d. |
The NaCl(aq) has no effect on the system. |
|
e. |
PbCl2(s) precipitates. |
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