Consider the following bivariate linear regression model y = a + Bx + u. Suppose that Cov(x, u) > 0, Cov(z,x) > 0, and Cov(z, u) = 0. Then, plim(BoLs) > B and plim(Brv) > plim(BoLs). %3D O True O False
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- The following fictitious table shows kryptonite price, in dollar per gram, t years after 2006. t= Years since 2006 0 1 2 3 4 5 6 7 8 9 10 K= Price 56 51 50 55 58 52 45 43 44 48 51 Make a quartic model of these data. Round the regression parameters to two decimal places.Olympic Pole Vault The graph in Figure 7 indicates that in recent years the winning Olympic men’s pole vault height has fallen below the value predicted by the regression line in Example 2. This might have occurred because when the pole vault was a new event there was much room for improvement in vaulters’ performances, whereas now even the best training can produce only incremental advances. Let’s see whether concentrating on more recent results gives a better predictor of future records. (a) Use the data in Table 2 (page 176) to complete the table of winning pole vault heights shown in the margin. (Note that we are using x=0 to correspond to the year 1972, where this restricted data set begins.) (b) Find the regression line for the data in part ‚(a). (c) Plot the data and the regression line on the same axes. Does the regression line seem to provide a good model for the data? (d) What does the regression line predict as the winning pole vault height for the 2012 Olympics? Compare this predicted value to the actual 2012 winning height of 5.97 m, as described on page 177. Has this new regression line provided a better prediction than the line in Example 2?QUESTION2 The data set provided by JOHN shows the number of yearly values of flood damage relief items represented by y and the annual rainfall (in centimetres) represented by x over a period of 10 years.y(000s) x (cm)4.0 1101.5 2501.2 2203.0 1503.0 4502.5 2002.0 2102.0 2301.1 2903.0 100 (a) Find the standard deviations of x and y. (b) Find the equation of the least-squares regression line, assuming that the value of the relief items for flood damage depend on the amount of rainfall. (c) Calculate the correlation coefficient using the…
- If there is a positive correlation between X and Y in a research study, then the regression equation Y = bX + a will have _____. Group of answer choices b > 0. b < 0. a > 0. a < 0.5.In a multiple regression analysis involving 15 independent variables and 200 observations, SST=800 and SSE 240. The coefficient of determination is A 0.700 B. 0.300 C. None D. 0.500 E 0.1921. Which of these X-Y relationships can be modeled as a simple linear regression model (e.g., with PROC REG in SAS)? a. A and B b. A and D c. A only d. Any of these For which of these sets of data would a simple linear regression model be appropriate? a. A and B b. A and D c. A only d. Any of these
- Question 21 Which of the following is a false statement? A) Since univariate models typically leave out lots of important RHS variables, we expect to have non-zero residuals B) A univariate regression model basically can’t be used to establish causality C) It’s always fine to assume linearity D) All of the above are correct statementsConsider the following model:? = ?? + ?,known as the Classical Linear Regression Model (CLRM), where y is the dependent variable, X is the set of independent variables, ? is the vector of parameters to be estimated and ? is the error term. Present and discuss the R2 and the adjusted R2. Discuss pros and cons of each of the two statistics.In an instrumental variable regression model with one regressor, Xi, andone instrument, Zi, the regression of Xi onto Zi has R2 = 0.1 and n = 50.Is Zi a strong instrument? Would your answer change if R2 = 0.1 and n = 150?
- Using the linear regression line from the sample, y = a + b x + e, if b = 0 then R 2 = 0. True/FalseWhich of the following represents the least-square regression line's equation? A. y = -a - bx B. y = a + bx C. y = a - bx D. y = -a + bxQuestion 1 Provide an algebraic proof that the least squares estimator is not consistent when Cov(x,e)=0 with the regression model y =B1+B2E(x)+e where E(e)=0So that E(y) = B1 + B2E(x)