Consider the following cases: Case 1: A rod with specified su temperature. Case 2: A rod with specified su temperature with heat generat Case 3: A rod with specified su temperature with variable ther conductivity k=k(1+ßT), ß: is ce The quadratic temperature pr« T(r)= f(r) will be in: Select one: A. Case (1) and Case (2) ONL B. Case (1), Case (2) and Ca

Consider the following cases: Case 1: A rod with specified su temperature. Case 2: A rod with specified su temperature with heat generat Case 3: A rod with specified su temperature with variable ther conductivity k=k(1+ßT), ß: is ce The quadratic temperature pr« T(r)= f(r) will be in: Select one: A. Case (1) and Case (2) ONL B. Case (1), Case (2) and Ca

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)

8th Edition

ISBN:9781305387102

Author:Kreith, Frank; Manglik, Raj M.

Publisher:Kreith, Frank; Manglik, Raj M.

Chapter1: Basic Modes Of Heat Transfer

Section: Chapter Questions

Problem 1.77P: 1.77 Explain each in your own words. (a) What is the mode of heat transfer through a large steel...

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1.77 Explain each in your own words. (a) What is the mode of heat transfer through a large steel plate that has its surfaces at specified temperatures? (b) What are the modes when the temperature on one surface of the steel plate is not specified, but the surface is exposed to a fluid at a specified temperature?
1.71 The thermal conductivity of silver at 212°F is 238 Btu/h ft °F. What is the conductivity in SI units?
The heat conducts through the shape below. The temperature of the right face is 93 °C, while the left face is at 23 °C. If the top and bottom faces are completely insulated, and the thermal conductivity of the material decreases with decreasing temperature. * Assume that the thermal conductivity is 100 at 23, decreased to 10 at 93. A) Sketch the temperature profile inside the plate. B) If both sides of the plate in the above problem is exposed to air: Left side (h = 20 W/m2K, TL = 20 °C) and right side (h = 90 W/m2K). Calculate the temperature of the air on the right side.
2. The drawing shows two thin rods, one made from aluminum Midpoint [a = 23 x 10-6 (C°)-'] and the other from steel [a = 12 × 10-“ (C°)-']. Each rod has the same length and the same initial temperature and is attached at one end to an immovable wall, as shown. The temperatures of the rods are increased, both by the same amount, until the gap be- tween the rods is closed. Where do the rods meet when the gap is closed? (a) The rods meet exactly at the midpoint. (b) The rods meet to the right of the midpoint. (c) The rods meet to the left of the midpoint. Aluminum Steel
25- c) A plane wall is having width ‘b’ mm and height 4 times of its width. The wall thickness is 120 mm. the thermal conductivity is 18 W/mK. The surface temperatures are at 700oC and 200o C The heat flow across the plane wall is 746 W Calculate the width, height and area of the wall?
A wall of a house is made from two layers of bricks enclosing a layer of insulation. A radiator is positioned to cover the whole internal surface, and used intermittently when the internal temperature is low. The external surface is exposed to the outside air. Which of the following assumptions could be used to identify the relevant reduced form of the conduction equation to find the temperature in the wall. a. Conduction is mainly in two directions. b. Conduction is mainly in one direction. c. The wall properties are homogeneous. d. Steady conditions exist. e. Unsteady conditions exist. f. There is an internal volumetric heat generation in the wall.
A square piece is initially at 10 degrees Celsius everywhere. Each side is 0.05 m long. Then the four sides are instantly heated up to 25 degrees Celsius, 50 degrees Celsius, 30 degrees Celsius, and 0 degrees Celsius. a. Find how long it takes for the temperature profile of this square to become steady if the material is copper. What is the final temperature at the center of the square? b. Find how long it takes for the temperature profile of this square to become steady if the material is air. What is the final temperature at the center of the square? c. Which material takes longer to reach steady state and why?
Question: USE CRANCK NICKLISON METHOD TO Find the steady state temperature distribution at all points of a heated steel plate .The plate has 30 cm width and 30 cm in length . The edges of the sheet are kept at constant temperature: 100 , 80 , 60 ,40 degrees. Assume the sheet is divided into 3x3 grids.
The rate of heat flow equation is Q O A. Thermal resistance OB. Thermal coefficient O C. None of these OD. Thermal conductivity Type here to search KA(T₁-T₂) X E The term X ΚΑ is known as 99+
What will be the rise in temperature in 30 minutes of a block of copper of 500-gram mass if it is joined to a cylindrical copper rod 20 cm long and 3.0 mm in diameter when a temperature difference of 80 degree Celsius is maintained between ends of the rod? The thermal conductivity of copper is 1.02 cal/cm2-sec-°C/cm (neglect heat losses). Please include FBD
The following graph shows the thermal behavior of 2 kg of a material called Uniandesato undergoing a solid-liquid phase transition. In a container, thermally insulated from the outside, 20 kg of liquid water at a temperature of 80°C are placed. In addition to this, an unknown amount of Uniandesato in a 100% solid state at its melting temperature (10°C) is added. The specific heat of water is 4186 J/kg°C. a) If the system reaches an equilibrium temperature of 60°C, calculate the initial amount of Uniandesato added to the container. b) Calculate the change in entropy during this process and show that it is consistent with the Second Law of Thermodynamics. Hint: Extract the necessary information to solve this problem from the graph.
8m long rod is at an initial temperature of 80c the left side of the rod is at temperature equal to 39c and the right side is at temperature equal to 68c thermal diffusivity is equal to 10^-4 and grid space is equal to 2m find the temperature distribution at 30_60_90 seconds