Consider the following code segment for a class named vehicle:class vehicle { private: string type; string model; string color; int numWheels; public: …};Write the PROTOTYPE for a function that overloads the + (plus) operator to add two vehicle objects. This prototype would add the numWheels of the objects. Write as a memberWrite the PROTOTYPE for a function that overloads the << (insertion) operator to print a vehicle object.

Answered: Consider the following code segment for…

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter10: Classes And Data Abstraction

Section: Chapter Questions

Problem 28SA

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Question

Consider the following code segment for a class named vehicle:

class vehicle {

private:

string type;

string model;

string color;

int numWheels;

public:

…

};

Write the PROTOTYPE for a function that overloads the + (plus) operator to add two vehicle objects. This prototype would add the numWheels of the objects. Write as a member
Write the PROTOTYPE for a function that overloads the << (insertion) operator to print a vehicle object.

Expert Solution

Step 1: Definitions

Operator overloading:

Operator overloading is giving new meaning or new definition to the existing operator but we cannot change the operator priority.

It is a compile time polymorphism in which operator is overloaded.
It simply means to do more than one task at a time on any operator.
Operators that cannot be overloaded are,

Scope resolution operator(::)
sizeof()
Ternary operator(?:)

Function prototype:·

The function prototype is used to declare a function.
It does not include the body of the function and informs the compiler about the function's name and return type.
The prototype specifies the list of arguments passed, if any, along with their data types.
The compiler makes use of prototype information to ensure the presence of corresponding function definition and correctness of argument data types.
In a function prototype, the name of the arguments is optional.
It is always terminated with a semicolon, unlike function definition which does not have a semicolon at the end.

Step 2: Answer for 1.

The prototype for a function that overloads the “+” operator is as follows,

vehicle operator + (vehicle const &v);

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