Consider the following reaction: 2 NO(g)  N2(g) + O2(g) The enthalpy change at 298 K for this reaction is Horxn = -180.74 kJ/mol. Under the same conditions the entropy change for the reaction is Sorxn = -24.71 J/mol-K. Calculate the value of Keq for this reaction at 8214 K. Assume that Horxn

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Q: Consider these two reactions: Reaction 1: 20F₂(g) → O₂(g) + 2 F₂ (g) AH = -49.4 kJ Reaction 2: N₂(g)…

A: ★ Answer : Reaction 2  is non spontaneous. ★ Explanation :

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Q: onsider the combustion reaction of ethane: 2 C2H6 (g) + 7 O2 (g)  6 H2O (g) + 4 CO2 (g) Which is…

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A: ΔSo = –549.73 J∙K–1 T = 298K ΔH = –824.2 kJ∙mol–1 = -824200 Jmol-1

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A: As per our guidelines we can only solve first question. Please resubmit other questions as next…

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Q: CuO (s) —> Cu (s) + 1/2 O2 (g) G = 155 kJ/mol A. Using the data in the table, calculate the value of…

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