Consider the following reaction at equilibrium. What effect will reducing the volume have on the system? C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(1) AH° = -2220 kJ No effect will be observed. The reaction will shift to the right in the direction of products. The equilibrium constant will increase. The reaction will shift to the left in the direction of reactants. The equilibrium constant will decrease.

World of Chemistry, 3rd edition
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Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
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Chapter17: Equilibrium
Section: Chapter Questions
Problem 39A
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Consider the following reaction at equilibrium. What effect will reducing the volume have on the system?
C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H20(1) AH° = -2220 kJ
No effect willI be observed.
The reaction will shift to the right in the direction of products.
The equilibrium constant will increase.
The reaction will shift to the left in the direction of reactants.
The equilibrium constant will decrease.
Transcribed Image Text:Consider the following reaction at equilibrium. What effect will reducing the volume have on the system? C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H20(1) AH° = -2220 kJ No effect willI be observed. The reaction will shift to the right in the direction of products. The equilibrium constant will increase. The reaction will shift to the left in the direction of reactants. The equilibrium constant will decrease.
Expert Solution
Step 1

Given reaction: C3H8 (g) + 5O2 (g) ↔ 3CO2 (g) + 4H2O (l)

We have to find the effect of reducing the volume on the system.

 

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