# Consider the following reaction:Br2(g)+Cl2(g)⇌2BrCl(g)Kp=1.11×10−4 at 150 K.A reaction mixture initially contains a Br2 partial pressure of 770 torr and a Cl2 partial pressure of 730 torr at 150 K.Calculate the equilibrium partial pressure of BrCl.

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Consider the following reaction:
Br2(g)+Cl2(g)⇌2BrCl(g)
Kp=1.11×10−4 at 150 K.
A reaction mixture initially contains a Br2 partial pressure of 770 torr and a Cl2 partial pressure of 730 torr at 150 K.

Calculate the equilibrium partial pressure of BrCl.

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Step 1

Partial pressure of a gas is defined as the pressure of that gas in a given mixture if it alone occupies the whole volume of  original mixture provided that the temperature remains the same.

Step 2

Partial pressure of a gas is defined as the notional pressure of that gas in a given mixture if it alone occupies the whole volume of  original mixture provided that the temperature remains the same.

In the above equation A, B, are the reactants and C, D are the products having a, b and c, d as the stoichiometric coefficients respectively.

Here Kp is the equilibrium constant which can be calculated from the partial pressures of the gases present in the given mixture of gases present in the chemical reaction.

Step 3

It is given that the initial partial pres...

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