Chemistry: The Molecular Science
5th Edition
ISBN: 9781285199047
Author: John W. Moore, Conrad L. Stanitski
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Textbook Question
Chapter 12, Problem 37QRT
Carbon dioxide reacts with carbon to give carbon monoxide according to the equation
At 700. °C, a 2.0-L sealed flask at equilibrium contains 0.10 mol CO, 0.20 mol CO2, and 0.40 mol C. Calculate the equilibrium constant KP for this reaction at the specified temperature.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionChapter 12 Solutions
Chemistry: The Molecular Science
Ch. 12.1 - The introduction to this chapter states that at a...Ch. 12.1 - Prob. 12.2CECh. 12.2 - After a mixture of cis-2-butene and trans-2-butene...Ch. 12.2 - Prob. 12.1PSPCh. 12.2 - Prob. 12.4ECh. 12.2 - When carbon dioxide dissolves in water it reacts...Ch. 12.2 - For each of these reactions, calculate KP from Kc....Ch. 12.3 - Prob. 12.3PSPCh. 12.4 - Suppose that solid AgCl and AgI are placed in 1.0...Ch. 12.4 - Prob. 12.6CE
Ch. 12.5 - For the equilibrium 2 SO2(g) + O2(g) 2 SO3(g) Kc...Ch. 12.5 - Prob. 12.7CECh. 12.5 - Prob. 12.6PSPCh. 12.5 - Prob. 12.7PSPCh. 12.6 - Prob. 12.8CECh. 12.6 - Prob. 12.9ECh. 12.6 - Prob. 12.10CECh. 12.6 - Prob. 12.8PSPCh. 12.7 - For the ammonia synthesis reaction
⇌
Does the...Ch. 12.8 - Prob. 12.13CECh. 12 - Prob. 1QRTCh. 12 - Prob. 2QRTCh. 12 - Prob. 3QRTCh. 12 - Decomposition of ammonium dichromate is shown in...Ch. 12 - For the equilibrium reaction in Question 4, write...Ch. 12 - Indicate whether each statement below is true or...Ch. 12 - Prob. 7QRTCh. 12 - Prob. 8QRTCh. 12 - Prob. 9QRTCh. 12 - Prob. 10QRTCh. 12 - The atmosphere consists of about 80% N2 and 20%...Ch. 12 - Prob. 12QRTCh. 12 - Prob. 13QRTCh. 12 - Prob. 14QRTCh. 12 - Prob. 15QRTCh. 12 - Prob. 16QRTCh. 12 - Prob. 17QRTCh. 12 - Prob. 18QRTCh. 12 - Prob. 19QRTCh. 12 - Prob. 20QRTCh. 12 - Prob. 21QRTCh. 12 - Prob. 22QRTCh. 12 - Prob. 23QRTCh. 12 - Prob. 24QRTCh. 12 - Prob. 25QRTCh. 12 - Prob. 26QRTCh. 12 - Prob. 27QRTCh. 12 - Prob. 28QRTCh. 12 - Prob. 29QRTCh. 12 - Prob. 30QRTCh. 12 - Given these data at a certain temperature,...Ch. 12 - The vapor pressure of water at 80. C is 0.467 atm....Ch. 12 - Prob. 33QRTCh. 12 - Prob. 34QRTCh. 12 - Prob. 35QRTCh. 12 - Prob. 36QRTCh. 12 - Carbon dioxide reacts with carbon to give carbon...Ch. 12 - Prob. 38QRTCh. 12 - Prob. 39QRTCh. 12 - Prob. 40QRTCh. 12 - Nitrosyl chloride, NOC1, decomposes to NO and Cl2...Ch. 12 - Suppose 0.086 mol Br2 is placed in a 1.26-L flask....Ch. 12 - Prob. 43QRTCh. 12 - Prob. 44QRTCh. 12 - Prob. 45QRTCh. 12 - Using the data of Table 12.1, predict which of...Ch. 12 - Prob. 47QRTCh. 12 - The equilibrium constants for dissolving silver...Ch. 12 - Prob. 49QRTCh. 12 - Prob. 50QRTCh. 12 - At room temperature, the equilibrium constant Kc...Ch. 12 - Prob. 52QRTCh. 12 - Consider the equilibrium N2(g)+O2(g)2NO(g) At 2300...Ch. 12 - The equilibrium constant, Kc, for the reaction...Ch. 12 - Prob. 55QRTCh. 12 - Prob. 56QRTCh. 12 - Prob. 57QRTCh. 12 - At 503 K the equilibrium constant Kc for the...Ch. 12 - Prob. 59QRTCh. 12 - Prob. 60QRTCh. 12 - Prob. 61QRTCh. 12 - Prob. 62QRTCh. 12 - Prob. 63QRTCh. 12 - Prob. 64QRTCh. 12 - Prob. 65QRTCh. 12 - Prob. 66QRTCh. 12 - Prob. 67QRTCh. 12 - Hydrogen, bromine, and HBr in the gas phase are in...Ch. 12 - Prob. 69QRTCh. 12 - Prob. 70QRTCh. 12 - Prob. 71QRTCh. 12 - Prob. 72QRTCh. 12 - Prob. 73QRTCh. 12 - Prob. 74QRTCh. 12 - Consider the system
4 NH3(g) + 3 O2(g) ⇌ 2 N2(g) +...Ch. 12 - Prob. 76QRTCh. 12 - Predict whether the equilibrium for the...Ch. 12 - Prob. 78QRTCh. 12 - Prob. 79QRTCh. 12 - Prob. 80QRTCh. 12 - Prob. 81QRTCh. 12 - Prob. 82QRTCh. 12 - Prob. 83QRTCh. 12 - Prob. 84QRTCh. 12 - Prob. 85QRTCh. 12 - Prob. 86QRTCh. 12 - Prob. 87QRTCh. 12 - Consider the decomposition of ammonium hydrogen...Ch. 12 - Prob. 89QRTCh. 12 - Prob. 90QRTCh. 12 - Prob. 91QRTCh. 12 - Prob. 92QRTCh. 12 - Prob. 93QRTCh. 12 - Prob. 94QRTCh. 12 - Prob. 95QRTCh. 12 - Prob. 96QRTCh. 12 - Prob. 97QRTCh. 12 - Prob. 98QRTCh. 12 - Prob. 99QRTCh. 12 - Prob. 100QRTCh. 12 - Two molecules of A react to form one molecule of...Ch. 12 - Prob. 102QRTCh. 12 - In Table 12.1 (←Sec. 12-3a) the equilibrium...Ch. 12 - Prob. 104QRTCh. 12 - Prob. 105QRTCh. 12 - Prob. 106QRTCh. 12 - Prob. 107QRTCh. 12 - Which of the diagrams for Questions 107 and 108...Ch. 12 - Draw a nanoscale (particulate) level diagram for...Ch. 12 -
The diagram represents an equilibrium mixture for...Ch. 12 - The equilibrium constant, Kc, is 1.05 at 350 K for...Ch. 12 - For the reaction in Question 111, which diagram...Ch. 12 - Prob. 113QRTCh. 12 - Prob. 114QRTCh. 12 - Prob. 115QRTCh. 12 - For the equilibrium...Ch. 12 - Prob. 117QRTCh. 12 - Prob. 119QRTCh. 12 - Prob. 120QRTCh. 12 - When a mixture of hydrogen and bromine is...Ch. 12 - Prob. 122QRTCh. 12 - Prob. 123QRTCh. 12 - Prob. 124QRTCh. 12 - Prob. 125QRTCh. 12 - Prob. 12.ACPCh. 12 - Prob. 12.BCPCh. 12 - Prob. 12.CCPCh. 12 - Prob. 12.DCPCh. 12 - Prob. 12.ECPCh. 12 - Prob. 12.FCP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Gaseous acetic acid molecules have a certain tendency to form dimers. (A dimer is a molecules formed by the association of two identical, simpler molecules.) The equilibrium constant Kp at 25C for this reaction is 1.3 103. a If the initial pressure of CH3COOH monomer (the simpler molecule) is 7.5 103 atm, what are the pressures of monomer and dimer when the system comes to equilibrium? (The simpler quadratic equation is obtained by assuming that all of the acid molecules have dimerized and then some of it dissociates to monomer.) b Why do acetic acid molecules dimerize? What type of structure would you draw for the dimer? c As the temperature decreases, would you expect the percentage of dimer to increase or decrease? Why?arrow_forwardKc = 5.6 1012 at 500 K for the dissociation of iodine molecules to iodine atoms. I2(g) 2 I(g) A mixture has [I2] = 0.020 mol/Land [I] = 2.0 108 mol/L. Is the reaction at equilibrium (at 500 K)? If not, which way must the reaction proceed to reach equilibrium?arrow_forwardKc for the decomposition of ammonium hydrogen sulfide is 1.8 104 at 25 C. NH4HS(s) NH3(g) + H2S(g) (a) When the pure salt decomposes in a flask, what are the equilibrium concentrations of NH3 and H2S? (b) If NH4HS is placed in a flask already containing 0.020 mol/L of NH3 and then the system is allowed to come to equilibrium, what are the equilibrium concentrations of NH3 and H2S?arrow_forward
- Gaseous acetic acid molecules have a certain tendency to form dimers. (A dimer is a molecule formed by the association of two identical, simpler molecules.) The equilibrium constant Kc at 25C for this reaction is 3.2 104. a If the initial concentration of CH3COOH monomer (the simpler molecule) is 4.0 104 M, what are the concentrations of monomer and dimer when the system comes to equilibrium? (The simpler quadratic equation is obtained by assuming that all of the acid molecules have dimerized and then some of it dissociates to monomer.) b Why do acetic acid molecules dimerize? What type of structure would you draw for the dimer? c As the temperature increases would you expect the percentage of dimer to increase or decrease? Why?arrow_forwardAt 2300 K the equilibrium constant for the formation of NO(g) is 1.7 103. N2(g) + O2(g) 2 NO(g) (a) Analysis shows that the concentrations of N2 and O2 are both 0.25 M, and that of NO is 0.0042 M under certain conditions. Is the system at equilibrium? (b) If the system is not at equilibrium, in which direction does the reaction proceed? (c) When the system is at equilibrium, what are the equilibrium concentrations?arrow_forwardThe equilibrium constant Kc for the synthesis of methanol, CH3OH. CO(g)+2H2(g)CH3OH(g) is 4.3 at 250C and 1.8 at 275C. Is this reaction endothermic or exothermic?arrow_forward
- An equilibrium mixture of SO2, O2, and SO3 at a high temperature contains the gases at the following concentrations: |SO2| = 3.77 103 mol/L, [O2] = 4.30 103 mol/L, and [SO3] = 4.13 103 mol/L. Calculate the equilibrium constant, Kc, for the reaction. 2 SO2(g) + O2(g) 2 SO3(g)arrow_forwardThe reaction PCl5(g) PCl3(g) + Cl2(g) was examined at 250 C. At equilibrium, [PCl5] = 4.2 105 mol/L, [PCl3] = 1.3 102 mol/L, and [Cl2] = 3.9 103 mol/L. Calculate Kc, for the reaction.arrow_forwardDinitrogen tetroxide, N2O4, is a colorless gas (boiling point, 21C), which dissociates to give nitrogen dioxide, NO2 a reddish brown gas. N2O4(g)2NO2(g) The equilibrium constant Kc at 25C is 0.125. What percentage of dinitrogen tetroxidc is dissociated when 0.0400 mol N2O4 is placed in a 1.00-L flask at 25C?arrow_forward
- The equilibrium constant (Kc) for this reaction is 1.60 at 990 c: H2(g)+CO2(g)H2O(g)+CO(g) Calculate the number of moles of each component in the final equilibrium mixture obtained from adding 1.00 mol of H2, 2.00 mol of CO2, 0.750 mol of H2O, and 1.00 mol of CO to a 5.00-L container at 990 c.arrow_forward12.103 Methanol, CH3OH, can be produced by the reaction of CO with H2, with the liberation of heat. All species in the reaction are gaseous. What effect will each of the following have on the equilibrium concentration of CO? (a) Pressure is increased, (b) volume of the reaction container is decreased, (c) heat is added, (d) the concentration of CO is increased, (e) some methanol is removed from the container, and (f) H2 is added.arrow_forwardA mixture of 0.0565 mol phosphorus pentachloride, PCl5, and 0.0800 mol helium gas, He, was placed in a 1.000-L flask and heated to 250.0C. The phosphorus pentachloride decomposes at this temperature to give phosphorus trichloride, PCl3, and chlorine gas, Cl2. The helium gas is inert. PCl5(g)PCl3(g)+Cl2(g) What is the partial pressure of helium in this equilibrium mixture at 250.0C? At equilibrium, the total pressure is found to be 6.505 atm. What is Kc for the dissociation of PCl5?arrow_forward
arrow_back_ios
arrow_forward_ios
Recommended textbooks for you
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
- Chemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage LearningChemistry by OpenStax (2015-05-04)ChemistryISBN:9781938168390Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark BlaserPublisher:OpenStaxGeneral Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry for Engineering Students
Chemistry
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Cengage Learning
Chemistry by OpenStax (2015-05-04)
Chemistry
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:OpenStax
General Chemistry - Standalone book (MindTap Cour...
Chemistry
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Cengage Learning
Chemical Equilibria and Reaction Quotients; Author: Professor Dave Explains;https://www.youtube.com/watch?v=1GiZzCzmO5Q;License: Standard YouTube License, CC-BY