Consider the reaction 6CO2(g) + 6H2O(l)C6H12O6 + 6O2(g) for which H° = 2.801×103 kJ and S° = -259.0 J/K at 298.15 K. (1) Calculate the entropy change of the UNIVERSE when 2.102 moles of CO2(g) react under standard conditions at 298.15 K. Suniverse = J/K (2) Is this reaction reactant or product favored under standard conditions?
Consider the reaction 6CO2(g) + 6H2O(l)C6H12O6 + 6O2(g) for which H° = 2.801×103 kJ and S° = -259.0 J/K at 298.15 K. (1) Calculate the entropy change of the UNIVERSE when 2.102 moles of CO2(g) react under standard conditions at 298.15 K. Suniverse = J/K (2) Is this reaction reactant or product favored under standard conditions?
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter13: Spontaneous Processes And Thermodynamic Equilibrium
Section: Chapter Questions
Problem 22P: Use data from Appendix D to calculate the standardentropy change at 25°C for the reaction...
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Consider the reaction
6CO2(g) + 6H2O(l)C6H12O6 + 6O2(g)
for which H° = 2.801×103 kJ and S° = -259.0 J/K at 298.15 K.
(1) Calculate the entropy change of the UNIVERSE when 2.102 moles of CO2(g) react under standard conditions at 298.15 K.
Suniverse = J/K
(2) Is this reaction reactant or product favored under standard conditions?
(3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction is reactant favored, choose 'reactant favored'.
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