Consider the reaction described by the equation С,Н, Вr, (aq) + 3Г (аq) — С,н,(8) + 2 Br (aq) + I5 (aq) The rate law is rate = k[C,H,Br,][I¯] where k = 0.00594 M-1. s-!. What are the missing entries in the table? Run [C,H,Br, lo (M) [I-], (M) Initial rate of formation of C,H, (M-s -) 1 0.245 0.00143 0.245 y 0.000713 3 0.245 0.245

Chemistry: The Molecular Science
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ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
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Chapter11: Chemical Kinetics: Rates Of Reactions
Section11.7: Reaction Mechanisms
Problem 11.12E
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Consider the reaction described by the equation
С,Н, Вr, (aq) + 3Г (аq) — С,н,(8) + 2 Br (aq) + I5 (aq)
The rate law is
rate = k[C,H,Br,][I¯]
where k = 0.00594 M-1. s-!.
What are the missing entries in the table?
Run [C,H,Br, lo (M) [I-], (M)
Initial rate of formation of C,H, (M-s -)
1
0.245
0.00143
0.245
y
0.000713
3
0.245
0.245
Transcribed Image Text:Consider the reaction described by the equation С,Н, Вr, (aq) + 3Г (аq) — С,н,(8) + 2 Br (aq) + I5 (aq) The rate law is rate = k[C,H,Br,][I¯] where k = 0.00594 M-1. s-!. What are the missing entries in the table? Run [C,H,Br, lo (M) [I-], (M) Initial rate of formation of C,H, (M-s -) 1 0.245 0.00143 0.245 y 0.000713 3 0.245 0.245
Expert Solution
Step 1

As per the given rate law, the reaction is first order in each of the reactant.

Step 2

At run 1:

Rate=k[C2H4Br2][I-]0.00143 M.s-1=(0.00594) M-1.s-1x(0.245 M)x=0.983 M

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