Consider the weak acids below and their corresponding Ka values. Rank the acids from weakest to strongest.HNO2 (Ka = 4.0 x 10-4)HIO (Ka = 2.0 x 10-11)C6H5COOH (Ka = 6.5 x 105)O (weakest) HNO2 < C6H5COOH < HIO (strongest)O (weakest) C6H5COOH < HIO < HNO2 (strongest)(weakest) HIO < HNO2 < C6H5COOH (strongest)O All weak acids are equally weakO (weakest) HIO < C6H5COOH < HNO2 (strongest)

Given Ka values: HNO2: (Ka = 4.0 x 10-4 ) HIO : (Ka = 2.0 x 10-11 ) C6H5COOH : (Ka = 6.5 x 10-5 )…

Consider the weak acids below and their corresponding Ka values. Rank the acids from weakest to strongest. HNO2 (Ka = 4.0 x 10-4) %3D HIO (Ka = 2.0 x 10-11) %3D C6H5COOH (Ka = 6.5 x 105) O (weakest) HNO2 < C6H5CO0H < HIO (strongest) O (weakest) C6H5COOH < HIO < HNO2 (strongest) O (weakest) HI0 < HNO2 < C6H5COOH (strongest) O All weak acids are equally weak O (weakest) HIO < C6H5COOH < HNO2 (strongest)

Consider the weak acids below and their corresponding Ka values. Rank the acids from weakest to strongest. HNO2 (Ka = 4.0 x 10-4) %3D HIO (Ka = 2.0 x 10-11) %3D C6H5COOH (Ka = 6.5 x 105) O (weakest) HNO2 < C6H5CO0H < HIO (strongest) O (weakest) C6H5COOH < HIO < HNO2 (strongest) O (weakest) HI0 < HNO2 < C6H5COOH (strongest) O All weak acids are equally weak O (weakest) HIO < C6H5COOH < HNO2 (strongest)

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter14: Acids And Bases

Section: Chapter Questions

Problem 94QRT: Several acids and their respective equilibrium constants are: Which is the strongest acid? Which...

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The following are equivalent ways of asking about the acidity of an H atom: • What is the most acidic H on the molecule? • Which H is associated with the published pKa value? • Which H on the molecule is easiest to remove? • Which H on the molecule takes the least energy to remove? • Which bond to an H is most polarized? • For which H atom is removal least uphill in energy? • Which bond to an H atom, when broken, results in the lowest PE conjugate base? We will often find the last of these questions is easiest to answer. To do this, find all the different Hatoms on the molecule, and draw all possible conjugate bases.Only the lowest-energy one is the “real” conjugate base. Identify this structure, and you have found the most acidic H. Use this strategy to find the most acidic H on each of the following molecules. Note: Each structure hasat least three different kinds of H’s, so draw at least three unique conjugate bases for each.
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