Construct a 90% confidence interval for H₁-H2 with the sample statistics for mean cholesterol content of a hamburgerfrom two fast food chains and confidence interval construction formula below. Assume the populations are approximatelynormal with unequal variances.Statsx₁ =99 mg, s₁ = 3.93 mg, n₁ = 18X280 mg, s2 = 2.02 mg, n₂ = 9Confidenceinterval when(x-x2)-tcvariances are notequal01+$2<ոշ

Given Data:For Sample 1:Sample size, n₁ = 18Sample mean, x̄₁ = 99Sample standard deviation, s₁ =…

Answered: Construct a 90% confidence interval for…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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An engineer designed a valve that will regulate water pressure on an automobile engine. The engineer designed the valve such that it would produce a mean pressure of 7.4 pounds/square inch. It is believed that the valve performs above the specifications. The valve was tested on 280 engines and the mean pressure was 7.5 pounds/square inch. Assume the variance is known to be 0.81. A level of significance of 0.05 will be used. Make a decision to reject or fail to reject the null hypothesis. Make a decision. Answer O Reject Null Hypothesis O Fail to Reject Null Hypothesis Tables: Keypad Keyboard Shortcut
Assume a researcher wants to compare the mean Alanine Aminotransferase (ALT) levels in two populations, individuals who drink alcohol and individuals who do not drink alcohol. The mean ALT levels for the individuals who do not drink alcohol is 32 with a standard deviation of 14, and 37 individuals were in the sample. The mean ALT levels for individuals who drink alcohol is 69 with a standard deviation of 19, and 38 individuals were in the sample. Construct and interpret a 95% confidence interval demonstrating the difference in means for those individuals who drink alcohol when compared to those who do not drink alcohol.
Medical researchers are interested in determining the relative effectiveness of two drug treatments on patients with a chronic mental illness. Treatment 1 has been around for many years, while treatment 2 has recently been developed based on the latest research. The researchers chose two independent test groups. The first group had 9 patients, all of whom received treatment and had a mean time until remission of 166 days, with a standard deviation of 8 days. The second group had 15 patients, all of whom received treatment 2 and had a mean time until remission of 161 days, with a standard deviation of 9 days. Assume that the populations of times until remission for each of the two treatments are normally distributed with equal variance. Can we conclude, at the 0.05 level of significance, that u, the mean number of days until remission after treatment 1, is greater than u,, the mean number of days until remission after treatment 2? Perform a one-tailed test. Then complete the parts…
A z-test is to be performed for a population mean. Express the decision criterion for the hypothesis test in terms of x. That is, determine for what values of x the null hypothesis would be rejected. ala After training intensively for six months, John hopes that his mean time to run 100 meters has decreased from last year's mean time of 11.8 seconds. He performs a hypothesis test to determine whether his mean time has decreased. Preliminary data analyses indicate that it is reasonable to apply a z-test. The hypotheses are Ho:u= 11.8 seconds H:u11.64 O Reject H, if x 11.61 Submit Assignment 2021 McGraw-Hill Education. All Rights Reserved. Terms of Use | Privacy II
Captopril is a drug designed to lower systolic blood pressure. In a trial, 12 randomly selected subjects were treated with the drug and another 12 randomly selected subjects were treated with the placebo. Assume the two populations are normally distributed. The results and some summary statistics are shown in the table. Note that some of the summary statistics may not be useful or relevant! Data Group Placebo 200 174 198 170 179 182 193 209 185 155 169 210 (ž1 = 185.3) (s1 = 17.1) Captopril (I2 = 166.8) (s2 = 14.9) d = I1 – 12 (d = 18.6) (sa = 10.1) %3D %3D 191 170 177 167 159 151 176 183 159 145 146 177 9. 4 21 3 20 31 17 26 26 10 23 33 %3D data %3D Using a 0.01 significance level, is there sufficient evidence to support the claim that the mean systolic blood pressure is lower for those treated with the drug than for those treated with the placebo? Use the p-value method. For full marks, include a diagram of the distribution indicating important components of the question.
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A market research group would like to know the satisfaction of subscribers in terms of the quality of service provided by Smart Communications and Globe Telecom. Using a survey, they gathered data from two independent samples. The data below summarizes the average customer satisfaction score (out of 10) towards the quality of services of their mobile providers. The satisfaction score is assumed to be normally distributed with unknown and UNEQUAL population variances. Statistics Smart Communications Globe Telecom Mean 4.20 3.15 Standard Deviation 1.25 2.25 Sample Size 25 20 a) Is there a difference in the average satisfaction scores of subscribers from Smart Communications and Globe Telecom? Make the comparisons at the 10% and 5% levels of significance. b) On average, are subscribers from Smart Communications more satisfied with their service provider than from the subscribers from Globe Telecom? Use the 5% and 1% levels of significance.
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The accompanying data represent the running times of files produced by two motion-picture companies. Assume that the running-time differences are approximately normally distributed. Construct a 90% confidence interval for 90% confidence interval for μ - μ were created, should it be assumed that o² = = If a Company | 106 96 105 Time (minutes) 91 99 II 101 78 123 89 171 89 120 Click here to view page 1 of the table of critical values of the F-distribution, for alpha = 0.05. Click here to view page 2 of the table of critical values of the F-distribution, for alpha = 0.05. The confidence interval is < (Round to three decimal places as needed.)

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