Construct a 95% confidence interval for the true proportion of all employees of Handy Glass Pty who are members of the company’s medical aid scheme, given that 75 out of a sample of 135 employees are members of the company’s medical aid scheme.

Q: (a) What is the rat's sample proportion p? What is the large-sample 95% confidence interval for p?…

A: Given: Population size, n = 80 Sample size, x = 80 Sample proportion, p^: p^=8080=1

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Q: Thirteen out of the 137 randomly selected faculty members who were surveyed at a community college…

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Q: The research group asked the following question of individuals who earned in excess of $100,000 per…

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Q: 11) In a Gallup poll, 1011 adults were asked if they consume alcoholic beverages and 64% of them…

A: (11) Obtain the 90% confidence interval estimate of the proportion of all adults who consume…

Q: The International Nanny Association (INA) reports that in a sample of 928 in- home child care…

A: Solution: A. Let X be the number of number of nannies who have passed the INA certification exam and…

Q: If a 0.10 significance level is to be used to test the claim that  p 1 less thanp 2​, what…

A: Provided that the level of significance is α=0.10.  Let p1 and p2 denote the population proportion…

Q: A university dean is interested in determining the proportion of students who receive some sort of…

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Q: Determine from a confidence interval whether a test is significant?

A: Null hypothesis states that there is no difference between populations or a set of given…

Q: In a survey with human resources managers, 71% of respondents thought they should hire new staff…

A: Given information: Denote the population proportion of all respondents who thought that they should…

Q: A &B

A: The provided data mentions the value of sample size, n is 928 and the value of x is 128. The…

Q: A cable company claims that 88% of its customers are fully satisfied with their service. A…

A: Given that  Sample size n =350 Favorable cases x =287 Sample proportion p^=x/n  =287/350 =0.82

Q: In September 2011, Gallup surveyed 1,004 American adults and asked them whether they blamed Barack…

A: It is given that sample size (n) is 1004 and p-hat value is 0.53.

Q: in a survey of 2230 adults, 57% thinks that land travel through a tourist bus is much more reliable…

A: Given,sample size(n)=2230sample proportion(p^)=0.57α=1-0.95=0.05α2=0.025Z0.025=1.96       (from…

Q: In an October 2003 poll conducted by the Gallup organization, 684 of 1006 randomly selected adults…

A: The confidence interval for the proportion of adults 18 and older who think the government should…

Q: In an article in Marketing Science, Silk and Berndt investigate the output of advertising agencies.…

A: Givenx=115n=390p^=xn=115390=0.2949confidence interval = 90%

Q: As customer satisfaction manager for a large utilities company, you randomly select 200 customer…

A: We have given that n = 200 x = 21 Confidence level (c) = 95% = 0.95

Q: Mr. Thomas of Wilmer Amina Carter High School (a large urban high school) wants to know what…

A: given that,possible chances (x)=85size(n)=152success rate ( p )= x/n = 0.5592

Q: search for the Ford Motor Company, you find that a random sample of 800 households includes 721 in…

A: At 98% confidence level, the z value is 2.33 which can be obtained by using the standard normal…

Q: It was observed that 30 of the 100 randomly selected students smoked. Find the confidence interval…

A: It is given that, 30 out of 100 randomly selected students smoked i.e. proportion of the student who…

Q: In a two-sided confidence interval involving two groups, when the signs of its lower and upper…

A: Confidence interval is an inference process which is used to estimate the population parameters…

Q: Alma is estimating the proportion of students in her school district who, in the past month, read at…

A: From the given information, n=50 and x = 32.

Q: Of 254 randomly selected medical students, 25 said that they planned to work in a rural community.…

A: It is given that, the number of students said that they planned to work in natural community   (x)…

Q: When 328 college students are randomly selected and surveyed, it is found that 122 own a car. Find…

A: We want to find 95% CI for population proportion (p)

Q: Determine the sample size necessary to construct a 95% confidence interval with an error of 0.08 if…

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Q: Of 346 items tested, 22 are found to be defective. Construct the 98% confidence interval for the…

A: Solution: Let X be the number of items found to be defective and n be the sample number of items…

Q: In order to judge the effectiveness of an advertising campaign for a certain brand of pretzel, a…

A: Let, 1: Before ad campaign 2: After ad campaign Given: n1=95X1=28       n2=65X2=33 α=0.02

Q: thirteen out of the 147 randomly selected faculty members who were surveyed at a communty college…

A: Solution: Let X be the number of faculty members at the community college who know sign language and…

Q: Suppose that a safety group surveyed 1,200 drivers. Among those​ surveyed,78​% said that careless or…

A: Obtain the 99% confidence interval estimate for the true proportion in the population of all drivers…

Q: Provide an explanation as to why it would be very unlikely that a different sample of size n=30…

A: Given: n=30

Q: According to some car loan statistics, 44% of Americans are relying on an auto loan to pay for their…

A: Givenp^=0.44sample size(n)=1500confidence interval = 95%

Q: consider a random sample of 300 students in a university, 75 of them declared that they like playing…

A: A random sample of 300 students in a university in which 75 of them declared that they like playing…

Q: Do younger people use Twitter more often than older people? In a random sample of 316 adult Internet…

A:

Q: Construct a 99% confidence interval for the true proportion of all car license applications that…

A: Given Information:x=25n=155c=99%=0.99

Q: In a sample of 500 Canadians, 225 say they would rather retire in Florida than in Canada. Calculate…

A:

Q: A survey found that out of 800 workers, 150 said they were interrupted by frank phone calls. Find…

A: Given,n=800x=150p^=xnp^=150800=0.18751-p^=1-0.1875=0.8125α=1-0.95=0.05α2=0.025Z0.025=1.96

Q: 2. A survey found that out of 900 workers, 150 said that they were interrupted by frank phone calls.…

A: In question, We have given the number of favorable cases 150 and sample size 900 then we'll find 95%…

Q: Construct a 99% confidence interval for the proportion of all motorbike license applications that…

A: We want to find the 99% confidence interval  Given  X=20 , n=175

Q: Construct a 90% confidence interval for the true proportion of all employees of People Plus Pty who…

A: Givenn=145x=130p^=xn=130145=0.8966α=1-0.90=0.10α2=0.05zc=z0.05=1.6449  (from z-table)

Q: In a survey of 500 potential jurors, one study found that 350 were regular watchers of at least one…

A:

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.